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HomeMy WebLinkAboutSW6140202_COMPLIANCE_20140311STORMWATER DIVISION CODING SHEET POST -CONSTRUCTION PERMITS PERMIT NO. SW_� DOC TYPE ❑ CURRENT PERMIT ❑ APPROVED PLANS ❑ HISTORICAL FILE COMPLIANCE EVALUATION INSPECTION DOC DATE z YYYYMMDD Wet Pond Calculations Project: Bedford — Section 1 Latitude: 35.0347 Long: 79.1270 Permitting Authority: State Regulatory Credits 85% TSS 25%Total Nitrogen 40% Total Phosphorus General Requirements Yes Sizing shall take into account all runoff at ultimate build out, including off -site drainage Yes Vegetated slopes shall be no steeper than 3:1. Yes BMP shall be located in a recorded drainage easement with access to a public ROW. Yes Per supplement form the wet pond is designed for 90%TSS removal. Basin discharge shall be evenly distributed across a minimum 30 feet long vegetative filter strip unless it is designed to remove 90%TSS. Yes The design storage shall be above the permanent pool. Yes Discharge rate of the treatment volume shall completely draw down between 2 and 5 days. Yes The average depth of the permanent pool shall be a minimum of 3 feet. (4 feet provided) Yes Permanent pool surface area shall be determined using Tables 10-1, 10-2, 10-3, and 10-4. Yes The flow within the pond shall not short circuit the pond. Yes BMP shall be designed with a forebay. Yes BMP shall not be located to produce adverse impacts on water levels in adjacent wetlands. Yes A minimum 10-foot wide vegetated shelf shall be installed around the perimeter. The inside edge of the shelf shall be 6" below the permanent pool elevation; the outside edge of the shelf shall be 6" above the permanent pool elevation. Yes The forebay volume should be about 20% of the total permanent pool volume, leaving about 80%of the design volume in the main pool. Yes Freeboard shall be a minimum of 1 foot above the maximum stage of the basin. SHWT: The permanent pool elevation shall be within 6 inches (plus or minus) of the SHWT elevation. SHWT: 193.56 Permanent Pool Elevation: 193.5 MAR 1 1 2014 Wafer Quality Treatment Volume Volume = 3630 * Rd * Rv * Ac Where Ac=[sf of Drainage Area]/43,560 sf/ac Rd = Design Storm I = Impervious Portion / Drainage Area Rv = 0.05 + 0.9 * I Ac= 92.3 1= 46.15/92.3 = 0.50 Rd = 1.0 Inches Rv= 0.05 + 0.9 (0.50) = 0.50 Volume = 3630 * 1.0 * 0.50 * 92.3 Acres = 167,524 cf Volume Provided: 198,300 cf Q: Discharge Rate (cfs) for 2 to 5 days Q = CdA [2 g HO] A 0.5 For a 6.0 inch diameter orifice r = 3 inches/12 inches/ft = 0.25 ft A=3.14r2=3.14(0.25)2=0.19625sf Cd = 0.6 g = 32.2 Ho = (Temporary Pool Elevation -Permanent Pool Elevation) / 3 = (195.0-193.5)/3 = 0.5 Q = 0.6 (0.19625) [(64.4) (0.5)] A 0.5 = 0.668 cfs Note: Q must be between Discharge Rate for 2 days and 5 days Discharge Rate (2-5 days) = Water Quality Treatment Volume/(seconds/dav)/(number of days) Q-Discharge Rate (2 days) = 167,524 cf / (86,200 seconds per day) / 2 = 0.97 cfs' Q-Discharge Rate (5 days) = 167,524 cf / (86,200 seconds per day) / 5 = 0.388 cfs Note: 0.97 cfs > 0.668 cfs > 0.388 cfs Surface Area (SA) provided: SA = DA/100 * Ratio Average Depth: 4.0 BUA1 = 50 % DA = Drainage Area = 4,020,588 sf Ratio= 2.5 (from Table 10-3 based on BUA, average depth, TSS and removal ) SA = DA/100 * Ratio = 4,020,588/100 * 2.5 = 100,512.5 sf SA provided: 121,191 ' Rough approximation that does not consider head