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HomeMy WebLinkAboutSW8021110_COMPLIANCE_20031218STORMWATER DIVISION CODING SHEET POST -CONSTRUCTION PERMITS PERMIT NO. SW _�yi�/l(_) DOC TYPE ❑CURRENT PERMIT ❑ APPROVED PLANS ❑ HISTORICAL FILE OMPLIANCE EVALUATION INSPECTION DOC DATE l.Y YYYYMMDD OF WATER Michael F_ Easley, Governor Q William G. Ross Jr., Secretary Go North Carolina Department of Environment and Natural Resources �—� Alan W. Klimek, P.E.,Director Division of Water Quality Coleen H. Sullins, Deputy Director Division of Water Quality December 18, 2003 Mr. Matthew T. Murphy, President Southeastern Enterprises, Inc. Managing Member SECOF, LLC Carolina Beach, NC 28428 NOTICE OF INSPECTION: Rachel Gardens Subdivision Stormwater Project No. SW8 021110 New Hanover County Dear Mr. Murphy: Please find attached a copy of the completed form entitled "Stormwater Compliance lnspection Report". The report summarizes the findings of a recent inspection of the project's stormwater controls conducted on December 15, 2003 to determine compliance with Stormwater Permit Number SW8 021110 issued on April 15, 2003. A summary of the findings and comments are noted under Section 4 of the report. Please inform this Office in writing before January 29, 2004, of the specific actions that will be undertaken and the time frame required to correct the deficiencies. Failure to provide the requested information, when required, may initiate enforcement action. If you have any questions please contact me at the Wilmington Regional Office, telephone number (910) 395-3900. Sincerely, Gary H. Beecher Environmental Technician RSSlghb: S:IWQSISTORMWATIINSPECT1021110.Dec03 cc: Wilmington Regional Office Beth Wetherill ( New Hanover County ) ►1S N. C. Division of Water Quality 127 Cardinal Drive Extension (910) 395-3900 Customer Service Wilmington Regional Office Wilmington, NC 28405 (910) 350-2004 Fax 1 800 623-7748 NCDENi i 1 � STORMWATER COMPLIANCE INSPECTION REPORT Project Name: Rachel Gardens Subdivision Project Number: SW8 021110 Control Measure: Detention Pond Water Body: Cape Fear/ Barnards Creek Stream Classification: "C Sw" Directions to site: 17th Street Extension,(L) on Steeple Chase, (R) on Chippenham Drive. 2. Inspection Date: December 15, 2003 Weather Conditions: Windy, Dry and Cold 3. Compliance Issues: Y N ❑ ❑ The drainage area (including offsite) and built -upon area to the permitted system are per the approved plan. No unpermitted offsite drainage enters the system. ❑ ❑ All the built -upon area associated with the project is graded such that the runoff drains to the system. ❑ ❑ For ponds/infiltration, the outlet/bypass structure relative elevations are per the approved plan. (Must be verified via as -built survey if in question). ❑ ❑ The inlets and outlet structure are located per the approved plans and do not cause short-circuiting. X ❑ A trash rack is provided over the outlet weir and orifice. ❑ X All slopes are grassed with permanent vegetation and are not eroding. ❑ ❑ Vegetated 'slopes are no steeper than 3:1. ❑ ❑ The approximate amount of permitted surface area has been provided. (Must be verified via as -built survey or designer's certification.) ❑ ❑ Required drawdown devices are correctly sized per the approved plans. All required design depths are provided. ❑ ❑ Allrequired parts of the system are provided, such as a vegetated shelf, and a forebay. ❑ ❑ The designer's certification has been submitted. ❑ The required deed restrictions are correctly recorded and submitted. ❑ The number of lots or outparcels is per the permitted amount. ❑ ❑ The built -upon area on the lots or outparcels does not appear to exceed the maximum amount (must be verified via as -built survey if in question) ❑ ❑ Curb outlet swales are constructed, located properly, are 100' long and have dense vegetated cover. ❑ ❑ The road, cul-de-sac, parking lot and sidewalk widths are per the approved plan. ❑ ❑ Required maintenance is being performed. ❑ ❑ Outparcels have their own offsite permit. ❑ ❑ For low density projects, roadside swales are 3:1, vegetated and stable. 00 For low density projects, there are no unpermitted pipes on the project. 4. Required Actions: (Explain each deficiency and what needs to be done to bring the system back into compliance) (a) The pond looks pretty good, there is a robust coverage of grass on most of the slopes. The only bad spot is on the Chippenham Drive side. More grass seed should be added to the bare spots, to ensure that the slope remains stabilized and erosion free. (b) I also noticed some large tire ruts that lead down the slope to the waters edge. These deep ruts will certainly cause erosion problems in the future unless they are grassed and stabilized now. (c) We also need a copy of the Deed Restrictions for Rachel Gardens Subdivision as soon as possible. Thank You Inspector: Gary H. Beecher Water Quality/Wilmington Regional Officel(910) 395-3900 RSSlghb: S:IWQSISTORMWATIINSPECT1021110.Dec03 WET DETENTION POND ANALYSIS FILE NAME: PROJECT #: SW8 021110 PROJECT NAME: Rachel Gardens Subdivision G :1DATAIWPDATAIWQSIPOND1021110. WK1 REVIEWER: L. Lewis DATE: 27-Mar-03 Receiving Stream: Barnards Creek Class: C Sw Drainage Basin: Cape Fear Index No. CPF17 18-80 Site Area 3.00 acres Drainage Area [ 30680:00, square feet Area in Acres 3.00 IMPERVIOUS AREAS Rational C 16 lots @2300 sq. ft. per lot 36800.00 square feet 1.00 Street 14019.00 square feet 1.00 SW 2735.00 square feet 1.00 square feet square feet square feet TOTAL 5354 00' square feet Rational Cc= 0.62 SURFACE AREA CALCULATION % IMPERVIOUS 40.98% Des. Depth 4 TSS: 90 SA/DA Ratio 3.58% Req. SA 4676 sf ,r Prov. SA 4i92: sf' VOLUME CALCULATION " place a "1" in the box if Rational is used Rational ?* 1 Des. Storm ...;1 Qtl<? inches Rv= 419 04119 Bottom 38.3 msl Perm. Pool ::.......42:3A. msl Design Pool 44.4 msl Storage met @elev 43.52 msl Req. Volume 712 < cf Vol. Prov. at DP 1734: cf ORIFICE CALCULATION Avg. Head = Flow Q2, cfs Flow Q5, cfs No. of Orifices Diameter, inches Drawdown = FOREBAY Perm. Pool Volume= 6772 Req. Forebay Volume= 1354.4 Provided Volume= 1426.00 Percent= Elevation Area Inc. Vol. Acc. Vol. 42.30 4692.00 0.00 0.00 43.80 6321.00 8259.75 8259.75 44.80 7479.00 6900.00 15159.75 COMMENTS Surface Area , Volume and Orifice are within Design Guidelines Entity Names http:/Iwww.secretary. state.nc.us/Corporations/soskb/Corp.asp?50604 North Carolina Elaine F. Marshall EPARTMEN T' OF THE Secretary SECRETARY of STATE PO Box 29622 Raleigh, NC 27626-0622 (919)807-2000 ,*Corporations Home.'. ,*Important Notice *Corporate Forms , Corporations FAQ !New Form Notice ,Business License . ,lRegisterforE-ProcuremE !Dept. of Revenue 999 Senate Bills 001 Bill Summaries knnual.Reports 1997 :orporations 1997 )they Leaislation eBy"Corporate Name 'For New Corporation !By Reqistered Agent Date: 1 /21 /2003 Document Filings Corporation Names Name Name Type SECOF, L.L.C. Legal Limited Liability Company Information SOSID: 0466715 Status: Current -Active Date Formed: 8/4/1998 Citizenship: Domestic State of Inc.: NC ._.._.Duration: .__7113/20,18........ Registered Agent Agent Name: Ken Coffer Construction, LLC Registered Office Address: #9 South Lake Park Blvd. Carolina Beach NC 28428 Registered Mailing Address: #9 South Lake Park Blvd. Carolina Beach NC 28428 Principal Office Address: 1202 N. Lake Park Blvd. Suite a Carolina Beach NC 28428 Principal Mailing Address: No Address Bar -Coded Forms For questions or comments about the North Carolina Secretary of State's web site, please send e-mail Webmaster. For questions or comri7ents concerning the Corporations Division, please send e-mail to Corporations Admij Click here for help downloading forms. 1 of 1 1 /21 /2003 12:05 QM Drainage Calculations for Chippenham Subdivision Wilmington, NC Project Number 02021 1114102 - Revised 12/15102, 1124/02 131069 Asite '= Asite = 3 acres 43560 0 Awetland '= Awetland = 0 acres 43560 Apond:= Asite Apond = 3 acres .....area on site draining to pond 0 Aoffsite := 43560 Aollsite = 0 acres .....offsite area draining to pond Atotal := Apond + AoMite Atotal = 3.0089 acres ...total area draining to pond Apatio := 100•16 Apatio - 0.04 acres .....patio 43560 Abld := 1400 16 Abld = 0,51 acres .....bldg g g 43560 Ag arag e = 0 15 acres .....garage Ag b arage: — 4 43560 3560 2735`a���e�saiaa�atpt,r Aside Aside - 0.1 acres on site sidewalk draining to pond ,�� ��PO rrr,,,� =`{ 43460 20.20.16QV Adrive '= Adrivc = 0.1 acres .....paved drives q: tty r 43560 12346 + 1673 Aroad — 43560 load 0.32 acres z 9524 road and curbing `ltv"N A = A + As• + A + Ar + Ap ,lr�ep.�r` + A imp Bldg ide drive oad duo garage Aimp = 1.23 acres ...impervious areas A A A 1 8 other := Atotal — imp other = • acres ...total area not impervious Cpre := 0.15 ...pre -development C Cimp := .95 ...paved area C Cbldg 1.00 ....building area C Aothcr Aimp (Abldg)] Ccomp Cpre- + Cimp' + Cbldg- Atotal Atatal Atotal Ccomp = 0.65 ...composite C (post -development) 1_ := 400 ft ...hydraulic length Fl := 3.8 ft ...height RE C E INT E. D JAW 3 0 2003 DW pgoj # S(Au3o ( 110 1 t ' Drainage Calculations for Chippenham 2 Subdivision Wilmington, NC L3 .385 0 .385 Tc :— i �] 28 < 5' S' H128 I'c = 5 ...time of concentration Intensity -Duration -Frequency Relationships: Values of G and H* 10 252 30 50 338 33 R= Return period *Source: City of Wilmington Technical Standards and Specifications Manual T.= if(TG < 5,5,"I'c) I' = 5 minutes Time of duration (use 5 minutes min.) G10:= 252 Hi0:= 30 110:= Gt0 110= 7.2 inlhr �1110 + 1 G50:= 338 f'50:= 33 150 :- G50 150 = 8.9 (1150 + 7 ) Compute runoff rates: Qloprc Cpre-110'(Atotal) Q10pre = 3.25 cfs Q50pre := Cpre-150"(AtatAl) Q50pCe = 4.01 cfs Q l 0 :- Ccomp' l l w (Atotal) Q 10 = 14.03 cfs inlhr 10 year storm intensity .50 year storm total pre -development runoff from 10 yr. storm total pre -development runoff from 100 yr. storm ... post -development discharge rate to pond from 10 yr. storm Q50:= Ccomp-150-(Atotal) Q50 = 17.34 cfs ... post -development discharge rate to pond from 50 yr. storm Volume of runoff from developed area of site: Pt0 := 4.82 in 1)50 := 6.42 in Soil type = Leon Fine Sand Drainage Calculations for Chippenham Subdivision Wilmington, NC IMP% := Aimp IMP% = 0.4086 total CN := IMP%-(98) + [(1 -- IMP%)-301 CN = 57.8 1000 S: CN — 10 S=7.3 Now compute runoff depth and time to peak for 10 yr. storm: (PIO — 0.2 S)2 RIOdepth := Pl0 + .8•S R10depth = 1.1 in. R10vol := Rlodepth•(Atotal)'435b()• 12TIO R10voi = 11557 R1Odepth'(Atotal) 43560, 1 1 1.39•(Q10) (12) 60 'I'10p = 9.87 ...time to peak flow T10 Curve No. ...runoff depth cubic feet ... runoff volume ATIO := P AT10 = I ...time increment for routing 10 year storm 10 Now compute runoff depth and time to peak for 50 yr. storm: (P50 — 0.2.S)2 R50depth := P50 + •8 SR50depth = 2 in. ...runoff depth 1 R50vol:= R50depth'(Atotal)•43560 12 T50p .— R50depth'(Atotal) 43560• I 1.39•(Q50) (112) 60 T50p = 15.15 ..time to peak flow R50vo1= 21902 cubic feet ... runoff volume T50 AT50 := p AT50 = 1.5 ...time increment for routing 50 year storm 10 Determine size of pond without vegetative filter: depth := 4 ft IMP% = 0.4086 i := 0.. 1 IMP%40 := .035 IMP°/a50:= .043 3 0 Drainage Calculations for Chippenham 4 Subdivision Wilmington, NC vx.:= x. IMP := linterp(vx, vy, IMP%• 100) IMP = 0.035691 DA := (Atotal).43560 SAfeq := (IMP)•DA SACeq 4678 sq.ft. ...Required surface area slope, := 6 ...min. slope of shelf slope2 := 2.5 ...min, slope of pond below shelf shelf := 2 ft. ...depth of shelf w:= (depth - shelf)•slope2.2 + shelf-slopel•2 w = 34 ...minimum width of permanent pool w := 34 ft. - width chosen [.= 3-w I = 102 ft. ...min. length of permanent pool 1 := 138 ft. - length chosen SAprov l-W SAprov = 4692 ...sq.ft. of surface area provided must be >= SA1Cq = 4678 Determine volume of permanent pool in order to size forebay: := 0 .. g k := 1.. 8 A. D.:-_ corresponding depth from contour above J J 2 ...area of contours t 629-ft .()-ft 772412 1-ft I 1 140-W 1-ftl 545•ft2 ]-ft 0•ft2 ]-ft I Vk := `-1 + -Dk ...incremental volume 2 0 Drainage Calculations for Chippenham Subdivision Wilmington, NC Vpond:_ I V ...total volume equals the sum of the incremental volumes Vpond = 6772 ft3 ...total volume in permanent pool Vrequired := •20'Vpond ...forebay volume equals 20% of total pool volume minimum Vrequired = 1354 113 ...eu.ft. required in forebay Determine volume in forebay: m := 0.. 8 n := L. 8 area := depm = corresponding depth from contour below m ...area of contours 0•ftl 0-ft2 67.5-ft2 t I •ft 180•ft2 I ] ft 583-ft2 I 1 •ft 1190.112 1 1 ft area + area n—I n vine := depn ...incremental volume n 2 Vforebay:= Nine ...total volume in forebay equals the sum of the incremental volumes V {forebay = 1426 fl3 ...total volume in forebay must be >= Vrequired = 1354 ft3 Vforebay. forebay := 100 forebay = 21.1 ...per cent forebay volume is of total pond volume Vpond Develop stage -storage function: m := 0.. 8 n := 1 ,. 8 eontour0 := 42.30 increment := .5 ...ft contour := contourn_I + increment contour = ...contours of proposed pond am := ...area of proposed pond contours (sq.ft.) 42.3 692 42.8 5217 43.3 5760 43.8 6321 44.3 6900 44.8 7497 45.3 8112 45.8 8745 4E3.3 9396 5 an -I + an vn2 • (contour n -- contour n- S0:= 0 ...initial storage Drainage Calculations for Chippenham Subdivision Wilmington, NC .incremental volume (cubic ft.) Sn Sn-I + vn ...cumulative storage (cubic ft.) stagcn := contour - conlouro InZn := In(stagcn) la! n -0.6931 0 0.4055 0.6931 0.9163 1.0986 12528 1.3863 stage = 0.5 1 1,5 2 2.5 3 3.5 4 ...natural log of stage S In 0 2477 5222 8242 11547 15146 19049 23263 27798 InSn := In(Sn) InS n 7.8149 8.5605 9.017 9.3542 9.6255 9.8547 10.054fi 102327 v m 0 2477.25 2744.25 3020.25 3305.25 3599.25 3902.25 4214.25 4535.25 ...natural log of storage L Drainage Calculations for Chippenham Subdivision Wilmington, NC x:= submatrix(ln%,2,6,0,0) y:= submatrix(InS,2,6,0,0) slope := slope(x,y) slope = 1.19 b := intercept(x,y) b = 8.55 K, := eh Ks = 5166 I S slope Zestm := m ...stage -storage function Ks L.estm = Should compare closely with : stagem = 0 0 0.54 0.5 1.01 1 1A9 1.5 1.98 2 2.5 2.5 3.03 3 3.59 3.5 4.18 4 Determine storage volume required for treatment of first inch of runoff: Ccomp = 0.65 1 V := 32 (Atowl)-43560•Ccomp V = 7076 cubic feet of storage required Solve for depth "d" to provide required storage for first inch of runoff: d := 1.5 ...guess value I•w + (1 + 6•d)•(w + 6•d) 1'(d) := .d ...function of d for rectangular pond w/3:1 side slopes 2 g(d) = V d := root[ (f(d) — g(d)), dl d = 1.31 ft. - depth required to provide required storage for 1 inch with site fully developed _ V 2day'� 2•24.60.60 2day— — 0.0409 V Q5day 5.24.60.60 Q5day = 0.0164 g := 32.2 Cdo := .6 cfs ...Max discharge for 2 day drawdown cfs ...Max discharge for 5 day drawdown .orifice coefficient 7 Drainage Calculations for Chippenham Subdivision Wilmington, NC h := d h = 0.66 ft ...avg. head 2 Q2day AoriGce 5 Aorifice = 0.011 Square ft. Cdo•(2•P'h) .5 1)2 (4. Aorifice • 12 D2 = 1.4 in. - for 2 day drawdown 3.14 Q5day = 0.0164 cfs Aorifcc •= Q5day 5 AoriGce = 0.004 Square ft. Cdo-(2-g•h) �,5.Aorificc D5 := 4 12 D5 = 0.9 in - for 5 day drawdown 3.14 Select drawdown orifice size: Do:= 1.125 in. Stage Discharge for Riser/Barrel Spillway with Emergency Weir: g := 32.2 ...acceleration due to gravity dia := 0 ...diameter of riser (ft.) (enter 0 if rectangular) len := 4 ...length of opening if rectangular (ft.) (enter 0 if circular) wid := 4 ...width of opening if rectangular (ft.) (enter 0 if circular) grate := 16 ...area of openings in grate if rectangular (enter 0 for circular) L:= i(dia * 0,7r-dia,2-(len + wid)] ...perimeter of riser (ft.) (dia)2 A:= i dia O,xc• ii(gratc # 0,grate, len•wid) 4 A = 16 ...area of riser as orifice (sq.ft.) Ltop := contour() + d Ltop = 43.61 ...minimum elevation of top of riser (ft.) 1'., = 44.40 ...chosen elevation for top of riser lop Cwr := 3.33 ...weir coefficient for riser CA,.:= 0.60 —Orifice coefficient of discharge for riser Nh := 1 ...Number of barrels Values for Orifice Coefficient of discharge: Dh := 15 ...diameter of barrel (in.) Entrance Condition CA Typical default value 0.60 Eb := 42.3 ...invert elevation of barrel must be a= contour, = 42.3 Square -edged entrance 0.59 my 0 Concrete pipe, grooved end 0.65 Cdb := 0.60 ...Orifice coefficient of discharge for barrel Corr mtl pipe, mitred to slope 0.52 corr mtl pipe projecting from fill 0.51 S Drainage Calculations for Chippenham Subdivision Wilmington, NC Check drawdown time when water level is at top of discharge structure: "oinv contour0 1)0 Elocl := contour0 + 12 li :_ (1'top — Eocl) 2 Eocl = 42.3 ...elevation of center line of orifice h = 1.027 ...avg. head do :_ o ft. -diameter of orifice 12 d 2 Aorificc := 3.14' 2 Aorifice - 0,0069 ...sq. ft. I q2:= Cdo'Aoriiicc'(2'g'h) 2 q2 = 0.0337 cfs Vtop KS {1 top — 1Ao,nv)slopc ft3 Vtnp - 12365 ft3 - volume of storage when water level Is at top of discharge structure - from stage -storage function q2 := q2-cf.5 q2 = 0.03 cfs drawdown:= Vtop q2 drawdown = 4.25 day Must be greater than or equal to 2 days and less than or equal to 5 days Check drawdown time of first inch when water level is at top of discharge structure: d = 1.31 ft. - depth required to provide required storage for 1 inch with site fully developed (from above) top — Eocl dactual l dactual - 2.05 .,.actual storage depth from orifice to top of discharge structure dremaining dactual — d dremaining = 0.74 ...depth remaining after 1 inch of storage has discharged III�dremainin} + d h, = 1.4 ft... average head 2 1 q3 := Cdo'Aoritice'(2'g'h1) 2 q3 = 0.0393 cfs ...discharge rate V := V-ft3 V = 7076 ft' - volume of storage when water level is at top of discharge structure (from above) �� drawdown V 1 g3•cfs drawdown, = 2.09day Must be greater than or equal to 2 days and less than or equal to 5 days ...O.K. 0 Drainage Calculations for Chippenham Subdivision Wilmington, NC Size overflow spillway to pass 50 year peak flow: Mew := .5 ..driving head over emergency weir (ft.) Cw := 3.0 ...weir coefficient for emergency weir _ Q50 .5 Cw' Hew' Lv = 8.2 ...ft. (minimum) Lw.= 10 ...ft. length chosen I-cr := 47.52 ...crest elevation of emergency weir inc := .2 ...amount to increment elevation (ft) I'topofbankmin Ecr + Ilew + 5 1=topotbankmin = 48.52 ft. minimum 1'topofbank = 48.52 ....selected top of bank elevation u := 0.. 25 v := l .. 25 elev0:= contour0 elevv:= clew-, + ine Calculate discharge through riser: hwu := clevu - l.top ...driving head for riser acting as a weir hou (clevu - Etop) ...driving head when riser is acting as orifice 3 rwu := i elevu - Etop S 0, 0, Cw,.•1. rhwu) 2 rout= if[(elevu) - I top <O,O,Cdr•A•`` 2•g•hou Calculate discharge through barrel: I D 2 barrel U:= i elevu 5 1 top,O,Nb•0.0437Cdb•Db2 elevu - �4 - Ebinv) Calculate discharge through orifice: For Z < or equal to Eo.inv: Q1 :=. 0 3 For Eo.inv <= Z <= D112 + Eo.inv Q2u := i elevu - Eoinv 5 0,0,0.372•Cdo•l)o (elevu - Eoinv) 2 1 I)o 2 1)o 2 For Z > D112 + Eo.inv: Q3u := i �elevu - 24 - Eoinv S 0,0,0.0437•Cdo•D0 elevu - 24 - Eoinv 10 Drainage Calculations for Chippenham Subdivision Wilmington, NC U orificcu := i elevu 5 Eoinv, Q 1, i elevu <-(12 - + Eoinv Q2u' Q3u 11 Calculate discharge through Principal spillway: Prince:= igelevuS Etop,O,min{rwc,rou,barrel u}} Calculate discharge over emergency weir: 3 weir u:= i elevu < Ecr,O,cN l-w•(elevu - Ecr)2 Calculate total discharge: discharge := Prineu + weir + orifice 11 Drainage Calculations for Chippenham Subdivision Wilmington, NC Print results: ft cfs cfs cfs cfs cfs cfs Cfs elevu rwu - roll = barrel = orifice = Princu = weir = dischargeu = 42.3 0 0 0 0 0 0 0 42.5 0 0 0 0.013 0 0 0.01 421 0 0 0 0.02 0 0 0.02 42.9 0 0 0 0.025 0 0 0.02 43.1 0 0 0 0.029 0 0 0.03 43.3 43.5 0 0 0 0.032 0 0 0.03 0 0 0 0.036 0 0 0.04 43.7 0 0 0 0.039 0 0 0.04 43.9 0 0 0 0.041 0 0 0.04 44.1 0 0 0 0.044 0 0 0.04 44.3 0 0 0 0.046 0 0 0.05 44.5 1.68 24.36 7.4 0.049 1.68 0 1.73 44.7 8.75 42.2 7.9 0.051 7.86 0 7.91 44.9 18.84 54.48 8.3 0.053 8.29 0 8.34 45.1 31.2 64.46 8.7 0.055 8.7 0 8.76 45.3 45.49 73.09 9.1 0.057 9.09 0 9.15 45.5 61.47 80.8 9.5 0.059 9.47 0 9.53 45.7 78.97 87.84 9.8 0.061 9.83 0 9.89 45.9 97.88 94.35 10.2 0.063 10.18 0 10.24 46.1 118.1 100.45 10.5 0.064 10.51 0 10.58 46.3 139.54 106.19 111.64 10.8 0.066 10.84 0 10.9 46.5 162.14 11.2 0.068 11.15 11.46 0 11.22 46.7 185.85 116.84 11.5 0.069 0 11.53 46.9 210.61 121.81 11.8 0.071 11.76 0 11.83 47.1 236.38 126.59 12.1 0.072 12.05 0 12.13 47.3 263.12 131.19 12.3 0.074 12.34 0 12.41 12 Drainage Calculations for Chippenham Subdivision Wilmington, NC COMPOSFIT STAGE- DISCHARGE, 280 260 240 220 200 180 100 80 60 40 20 0 42 42.5 43 43.5 44 44.5 45 45.5 46 46.5 47 47.5 STAGE {ft} — riser as weir I-.""""' riser as orifice ------- barrel ""-'-'- overflow weir 13 47.5 47 46.5 46 ,, 45.5 45 W C7 Q 44.5 44 43.5 43 42-5 42 0 Drainage Calculations for Chippenham Subdivision Wilmington, NC NET STAGE DISCHARGE 2 4 6 8 10 12 14 DISCII&RGG (efs) 14 Drainage Calculations for Chippenham Subdivision Wilmington, NC Set up matrix to do 10 year storm routing: XF := ATI O Q := Q10 Tp := T1Op iter := 60 ...number of iterations u := 0.. iter m := 0.. 10 M = sal u,m' M <-- 0 0, m clev, <-- contour, while s 5 iter IV+--S .set variables for storm to be rotated My 0 M(v--1 0) + AT — 1.3• Mv,o 'r My I < if My , < 0,0,i My , 5 1.25•'rp, Q 1 �- cos v'O ,4.34•Q•e p 2 rp My2 iCMV-1,I—Mv-1,7)-Nh'60+My-1,2<O'0'(Mv—],I—MV-1,7)-AT•60+My-1,21 M slope My 3 <— i �Mv 2) O,contouro, v'2 + contour, ' Ks rwV ilJ My 3 — Etop <— 0,0,cwr•L•(Mv 3—'-top)I.51 roV F iVMv 3) — Etop < 0,0,Cdr•A' 2•g My 3 11— Etop 2 Dh �0.5] barrels +--it My 3 S Etop,0,Nh•0.0437•Cdb•Db (Mv,3 - 24 — Ebinv Q2 <— iM — I;o• <_ 0 0,0.372•C D (M Eo• )1.51 v v,3 inv do o v,3 _ my J 0.5 Q3v i (Mv,3 — D4 — Eoir, < 0,0,0.0437•Cdo•Do2(Mv3 — 24) — Eoinv My4<— i My3S Eoinv,Ql,i My3T)o 122 + Foinv Q2v' Q3v II My 5 if(My 3 S l top,O,minrrwv,roy,barrelV)) ` My 6 i�My 3 <Ecr,0,Cw•Lw. My 3 — Ecr)1.51 My 7�My 4+My 5+Mv 6 s+—s+ I M u, m 15 Drainage Calculations for Chippenham Subdivision Wilmington, NC discharge := Mu 7 Q 1 Omax:= max(discharge) stage := Mu 3 Ql Ostage := max(stage) Q1 Omax = 0.05 cfs ...must be <= Q10pre = 3.2 Ql Ostage = 44.3 ft. Check mass balance of matrix talcs; Storage := Miter, 2 Storage = 11451 iter l Inflowtotal := I F(Mv-1, 1)-[(A1).60]11 lnflowtotal = 11556 v=l iter Outflowtotal:= I[[(Mv-1,5+Mv-1,6+Mv-1,4)-F(Xr)-60]J_Il1 Outflowtotal= 135 v= 1 Inflowtotal - Outflowtotal = 11451 MIST BE REASONABLY CLOSE TO Storage = 11451 O.K. Display a portion of routing results: tirneu Mu 0 inflow := Mu 1 storage := Mu 2 stage := Mu 3 orificeIt:= Mu 4 culvertu := Mu 5 weir := Mu 6 discharge := Mu � a (See next page for display) cfs O. K. 16 Drainage Calculations for Chippenham Subdivision Wilmington, NC Partial TIME minutes time display of INFLOW = 10 year cfs inflow = 0 0.3 1.3 2.9 4.8 7 9.2 11.1 12.7 13.7 14 13.7 12.7 11.2 9.9 8.7 7.6 6.7 5.9 5.2 4.5 4 3.5 3.1 2.7 2.4 2.1 1.8 1.6 1.4 1.2 1.1 1 0.81 0.7 0.6 storm routing results: STORAGE cubic feet storage = 0 0 20 100 271 558 973 1516 2175 2926 3736 4565 5375 6125 6788 7371 7882 8331 8724 9069 9372 9638 9870 10074 10253 10410 10547 10668 10773 10865 10945 11016 11077 11131 11178 11218 STAGE ft stagcu = 0 42.3 42.31 42.33 42.38 42.45 42.54 42.65 42.78 42.92 43.06 43.2 43.33 43.46 43.56 43.65 43.73 43.8 43.86 43.91 43.96 44 44.03 44.06 44.09 44.11 44.13 44.15 44.17 44.18 44.19 44-21 44.21 44.22 44.23 44.23 ORIFICE CULVERT cfs orifiiccu = 0 0 0 0 0.01 0.01 0.01 0.02 0.02 0.03 0.03 0.03 0.03 0.03 0.04 0.04 0.04 0.04 0.04 0.04 0.04 0.04 0.04 0.04 0.04 0.04 0.04 604 0.04 0.04 0.05 0.05 0.05 0.05 0.05 0.05 cfs culvert = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 WEIR cfs weir - 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 DISCHARGE cfs discharge _ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 3 3.9 4.9 5.9 6.9 7.9 8.9 9.9 10.9 11.8 12.8 13.8 14.8 15.8 16.8 17.8 18.8 19.7 20.7 21.7 22.7 23.7 24.7 25.7 26.7 27.6 28.6 29.6 30.6 31.6 32.6 33.6 34.6 17 Drainage Calculations for Chippenham Subdivision Wilmington, NC Cl IAINSAW ROUTING FOR 10 YI AR STORM 15 14 13 12 11 10 9 6 5 4 3 2 1 0 - -- - ----- -- - - - -------------------- - - 0 10 20 30 40 50 60 TIME (minutes) inflow ------- outflow 18 Drainage Calculations for Chippenham Subdivision Wilmington, NC Change variables to do 50 year storm routing: AT:= A'I'50 Q := Q50 Tp := 'I'50p M = s<--1 u,m' MO mF0 clev0 <-- contour0 while s 5 iter IV<—s ...set variables for storm to be routed My 0 <- M(v-1,0) + AT - rp l.3• M" My 1 <- i My 0 < 0,0, i My 0 S 1.25-"1'P, Q • 1 -cos v'0 ,4.34•Q•e 2 Tp )) My 2 <-- flM V--I 1 - My-1 7)•A"I'•60 + My-1, 2 5 0,0,(Mv-1, I - My-1, 7)•A"I'•60 + My -I 21 1 M 2 slope My 3 <- i (Mv 2) S O,contour0' v, + contour0 ' Ks rwv ill My 3 - Etop <- 0,0,Cwr'I: rMv,3 - Eta )1.51 LL ` I' J rov <- if��Mv 3} - Et5 O, 0, Cdr-A• 2 g My 3 - Etop 2 Db 0.5 barrel y <- i My 3 5 Etop,O,Nb•0.0437•Cdb•Db (Mv 3 - 24 - Ehinv) Q2 <-- if[ M - Eo <- 0 0 0.372•C D •(M Eoe, )1.51 v v, 3 my > > do• o v 3 - nv 1)0 2. 1)o 0.5 Q3v +- i My 3 - 24 - Eoit, 5 0,0,0.0437•Cdo•Do (Mv 3 24 - Eoinv 1 I)o 1 My 4 <- i My 3 5 Eoinv,Ql,' My 3 5 (12 + Eoinv1,Q2v'Q3v 11 My 5 F if(Mv 3 -< Etop10,min(rwv,rovIbarrel v)) My 6 +- iItMv 3 < Ecr,0,Cw I -W. (Mv, 3 - Ecr)1.5] My 7<-Mv 4+Mv 5+Mv 6 s<--s+1 I Mu, m discharge := Mu, 7 Q50max:= max(discharge) Q50max = 7.9 Cfs _ stage ' u, 3 Q50stage : = max(stage) Q50stage = 44.71 ft. 19 Drainage Calculations for Chippenham Subdivision Wilmington, NC 20 time := Mu 0 inflow := Mu t storage := Mu 2 stage := MU 3 orifice := Mu 4 culvert := Mu 5 weir := Mu 6 discharge := Mu 7 Partial display of 50 year storm routing results: TIME INFLOW STORAGE STAGE ORIFICE CULVERT WEIR DISCHARGE minutes cis cubic feet ft cfs cfs cfs cfs time = inflow = storage = stageu = orifice = culvert = weir = dischargec = 0 0 0 0 0 0 0 0 1.5 0.4 0 42.3 0 0 0 0 3 1.7 39 42.3 0 0 0 0 4.5 3.6 189 42.4 0 0 0 0 6.1 6 513 42.4 0.01 0 0 0 7.6 8.7 1057 42.6 0.02 0 0 0 9.1 11.3 1843 42.7 0.02 0 0 0 10.6 13.8 2873 42.9 0.02 0 0 0 12.1 15.7 4122 43.1 0.03 0 0 0 13.6 16.9 5544 43.4 0.03 0 0 0 15.1 17.3 7078 43.6 0.04 0 0 0 16.7 16.9 8651 43.8 0.04 0 0 0 18.2 15.7 10184 44.1 0.04 0 0 0 19.7 13.9 11605 44.3 0.05 0 0 0 21.2 12.2 12863 44.5 0.05 1.02 0 1.1 22.7 10.7 13874 44.6 0.05 5.34 0 5.4 24.2 9.4 14357 44.7 0.05 7.82 0 7.9 25.8 8.3 14495 44.7 0.05 7.87 0 7.9 27.3 7.2 14526 44.7 0.05 7.88 0 7.9 28.8 6.4 14464 44.7 0.05 7.86 0 7.9 30.3 5.6 14323 44.7 0.05 7.81 0 7.9 31.8 4.9 14117 44.7 0.05 6.67 0 6.7 33.3 4.3 13952 44.6 0.05 5.76 0 5.8 34.8 3.8 13815 44.6 0.05 5.04 0 5.1 36.4 3.3 13697 44.6 0. 55 4.44 0 4.5 37.9 2.9 13591 44.6 0.05 3.92 0 4 39.4 2.6 13495 44.6 0.05 3.47 0 3.5 40.9 2.2 13408 44.5 0.05 3.08 0 3.1 42.4 2 13328 44.5 0.05 2.74 0 2.8 43.9 1.7 13254 44.5 0.05 2.43 0 2.5 45.4 1.5 13186 44.5 0.05 2.16 0 2.2 47 1.3 13124 44.5 0.05 1.92 0 2 48.5 1.2 13067 44.5 0.05 1.71 0 1.8 4451.52 "0013014 0 1.6 Drainage Calculations for Chippenham Subdivision Wilmington, NC CHAINSAW ROUTING FOR 50 YEAR STORM 18 16 14 12 6 4 2 0 0 10 20 30 40 50 60 70 80 90 100 TIME (minutes) — inflow "'- outflow 21 W Drainage Calculations for Chippenham Subdivision Wilmington, NC Determine outlet apron dimensions and riprap size for pipe discharge to pond from SD MH 2: 1):= 2 ...ft - diameter of pipe Voutict := 2.8 fps - from pipe sizing chart From Figure 8.06.b.1 and Figure 8.06.b.2 choose Zone 1. I -a := 4•1) I,a = 8 ft - minimum length of apron from figure 8.06b2 W := 3.1) W = 6 ft - minimum width of apron from figure 8.06b2 dia := 6 diameter of stone in inches dmax.= 1.5•dia dmax = 9 max stone diameter t := 18 in. min. thickness of apron in inches Determine outlet apron dimensions and riprap size for pipe discharge to pond from Curb Inlet 4: D := 1.25 ...ft - diameter of pipe Voutict :- 3•3 fps - from pipe sizing chart From Figure 8.06.b.1 and Figure 8.06.b.2 choose Zone 1. I -a := 4-D La = 5 ft - minimum length of apron from figure 8.06b2 W := 3•D W = 3.8 ft - minimum width of apron from figure 8.06b2 dia := 6 diameter of stone in inches dmax:= 1.5•dia dmax = 9 max. stone diameter t := I8 in. min. thickness of apron in inches Note: References to chart nos., table nos., and page nos. refer to Erosion and Sediment Control Planning and Design Manual unless noted otherwise M ` -'Yl am l az�Lt QV Ua- _ _ ate. u.1,i;Q;P �lw_n NOV 5 �.l �Op1