HomeMy WebLinkAboutSW6201202_Calcs (Ditch)_202012101691- Faithwill Farms Subdivision
Ditch Calculations
Q = 2.53 cfs
Ditch #1
Ditch #5
Road A Sta. 4+00 to 8+00 right
Road A Sta. 2+50 to 4+00 left
Tc = 31.6 min; use 30 min
Tc = 5 min
Kerby: L = 430 If; s = 0.005; n = 0.4
DA = 0.12 ac
DA=1.22ac
C=0.8
C=0.45
1=7.90in/hr
I = 3.86 in/hr
Q = 0.76 cfs
Q = 2.12 cfs
Ditch #6
Ditch #2
Road A Sta. 0+00 to 2+50 left
Road A Sta. 2+50 to 4+00 right
Tc = 5 min
Tc = 21.7 min; use 15 min
DA = 0.15 ac
Kerby: L = 191 If; s = 0.005; n = 0.4
C = 0.8
DA = 0.51 ac
I = 7.90 in/hr
C = 0.45
1 = 5.33 in/hr
Q = 0.95 cfs
Q = 1.22 cfs
Ditch #7
Ditch #3
Tc = 30 min
Road A Sta. 0+00 to 2+50 right
DA = 3.60 ac
C = 0.45
Tc = 45 min
I = 3.86 in/hr
DA = 3.09 ac
C=0.45
Q=6.25cfs
I = 3.19 in/hr
Ditch #8
Q = 4.44 cfs
Tc = 45 min
Ditch #4
DA = 4.25 ac
Road A Sta. 4+00 to 8+00 left
C = 0.45
1 = 3.19 in/hr
Tc = 5 min
DA=0.40
Q=6.10cfs
C=0.8
1 = 7.90 in/hr
Koaa H Jia. 4+uu io zS+uu leii U = u.45
I = 3.19 in/hr
Tc = 5 min
DA=0.40 Q=6.10cfs
C=0.8
1 = 7.90 in/hr
Koaa H Jia. 4+uu io 6+uu leii u = u.4.7
I = 3.19 in/hr
Tc = 5 min
DA=0.40 Q=6.10cfs
C=0.8
1 = 7.90 in/hr
Koaa H Jia. 4+uu io 6+uu leii u = u.4.7
I = 3.19 in/hr
Tc = 5 min
DA=0.40 Q=6.10cfs
C=0.8
1 = 7.90 in/hr
Koaa H Jia. 4+uu io 6+uu leii u = u.4.7
I = 3.19 in/hr
Tc = 5 min
DA=0.40 Q=6.10cfs
C=0.8
1 = 7.90 in/hr
Koaa H Jia. 4+uu io 6+uu leii u = u.4.7
I = 3.19 in/hr
Tc = 5 min
DA=0.40 Q=6.10cfs
C=0.8
1 = 7.90 in/hr