Energy Dissipator Calculations (1)

Appendices
FES 2
Q=(,30)'(7.04 in/hr)"7.910ac
4/26/19 KCG
i
� • i+:1f:11r�1r�
.61'Al':1■ ■
. IoAM 1111WAId A IF
P�'N'.�f
{ .Illi 1 ■rill Ifl'lf'�nNl
{ , . �I,lill �l1113111111�II i II ullll;ji
Il IIlII•� "Inllh�p
I f1111111 I�Ilnl'In1
�-- I� II1111 ■ ii �! II; I
dull P i�lrnf.l�:i+�
11 f.r iWIanii
PP�Iill41lip1! FIop
� 1lrl Illd11-lil
�I�pp n I IIIIIIQm'!Inlnu°" .► r
1 IiHfi`fffllflfnlfl11111 ikllliii�fiNA�� Uo'N1i.1NOl.r'��1lIdpltll. !'it'. �;ul,ilril • tf1�
1 n11 ua Inl 11 1`w fl111 • �wifPIif�..�`'a•11ii1154-:ii� 0f0 • ' lnl
11 If I {IIII 1 tf� 1 f!! ��� �!/�•' 3 �p11
lS l ielil i .,��r'1111 11111 li II •
■li e•:llli•I �
rn n of 1 I • TIAlPdlI:IAIP..Iilii�li 1f11it Ill'
WIN.
11 �li:`�ll'1IfI11'{d { rH IIIII
1f�1�Nlf�I ! = �l: f 1111� `�!!1 II llfl!-� •
�����ilf�� ' .11�ll►'i�l.lii�� wl�� Ipi�i�iii�i������fii1�iiii����iP���irninll
.::won
1
1 1 1 11 11 11 111
Curves may not be extrapolated.
Figure 8.06a Design of outlet protection protection from a round pipe flowing full, minimum tailwater condition (TW < 0.5 diameter).
Rev. 12/93 8.06.3

Appendices
FES 4
Q=(.30)'(7.04 in/hr)'4.24 ac
4/12/19 KCG
375
3a
14.25 I
Outlet W = Do + La 90 1
pipe
diameter (Do) ;.....I
10La $0
i,
T ilwater 0.5Dp
7Q
W � o I
50
tk
50
4.) - 1.
.. :..... ... � d ' .
105
...--- .............. ...
3 5 ' "•"10 20 50 100 200
Discharge (0/sec)
4
3
m
2 N
a
c�
a
0
1 -o
500 1000
Curves may not be extrapolated.
Figure 8.06a Design of outlet protection protection from a round pipe flowing full, minimum tailwater condition (Tw < 0.5 diameter).
Rev. 12/93 8.06.3

Appendices
FES 5
Q=(_30)'(7-04 in/hr)'2.51ac
4/15/19 KCG
1
• 1�
l:ln': dip '
• 1tl' I�I I' I'1.1
• VJimd I
II
lAI'flll'Irll
_ •rwAr..i AII�;f�ld.�I
YWl!}111�1I1N_.YIL.i••., tt .* ► ,'�j1 Nip• l��r"•
JiMN
/fl lii'll.l�llN UP • • pI
,
�� � � ��rwl�rl �� �YFIIINI •
1
1 1 1 II II 11 111
K 1 1, 1 11. .. 1
Rev. 12/93 8.06.3

Appetrdices
FES
Q=(.30)*(7.04 in/hr)*5-52ac
4/15119 KCG
45
3 .o
14.75
Outlet W = Do + La 90
pipe E
diameter (Do) - ,
10La5 �a 30
7 ilw ter t 0.5De ;;
•�• I •>y b� I �
IF:i.
4
4
3
F
a>
Z N
d
n�
a
0
1 a
" 0
1000
Curves may not be extrapolated.
Figure 8.06a Design of outlet protection protection from a round pipe flowing full, minimum tailwater condition (TW < 0.5 diameter).
Rev. 12/93
8.06.3

0�j
12.75
Outlet W = Do + La
pipe
diameter (Do)
Lam
T ilwater c 0.51)o
IA)
1- �gljQt� `CP
e�g�r
Ot �� Fill
t ..
50 100
Discharge (ft3/sec)
,41pe►►dices
FES 10
Q=(.30)'(7.04 in/hr)`.308 ac
4/15/19 KCG
F-
a)
2 N
W
CL
(U
LO
_ L1
O
1 '0
"0
1000
Curves may not be extrapolated.
Figure 8.06a Design of outlet protection protection from a round pipe flowing full, minimum tailwater condition (TW < 0.5 diameter).
Rev. 12/93 8.06.3

9
Appendices
FES 12
Q=(0.30)*(7,04 in/hr)*3,24 ac
4/11/19 KCG
375
ao
10.25
Outlet W = Do + La
pipe
diameter (Do)
i ilwater - 0.51)o
>yA4"c— t01`�-azA*')
`r of Pp 60
r
3 5 6 s4 cfs 10 20 50 100 200 500 1000
Discharge (0/sec)
Curves may not be extrapolated.
Figure 8.06a Design of outlet protection protection from a round pipe flowing full, minimum tailwater condition (Tw < 0.5 diameter).
Rev. 12/93 8.06.3

20
10
0
375
3 0
10.25
Outlet W = Do + La
pipe
diameter (Do)
La�
T ilwater 0.5Do
l�l
Opp. hfl �-
lr
50
90
I .
AppeiirGces
FES 13
Q=(0.80)'(7.04 in/hr)'0 64 ac
4/12/19 KCG
a)
2 N
U)
a
E5
irn
0
1 LO
L
1. _ I I , I I I I I I I I i 1" 10
3 5 10 20 50 100 200 500 1000
Discharge (ft3/sec)
Curves may not be extrapolated.
Figure 8.06a Design of outlet protection protection from a round pipe flowing full, minimum tailwater condition (Tw < 0.5 diameter).
Rev. 12/93 8.06.3