HomeMy WebLinkAbout03_20200914 ADI Response 7-20-2020 - S&EC calcs ■
A & H MINE
401 SAND COMPANY, LLC
SEDIMENTATION & EROSION CONTROL
CALCULATIONS
RECEIVED
SEP 14 Y020
LAND QUALITY
MINING PROGRAM
Prepared By: ,e�G�iDo,,
601
UF,. ,
L�L4 Lr' 4 •
ENGINEERING " SURVEYING
CORPORATE LICENSE:C-177 1 /
1 01 W. MAIN ST., SUITE 202 .V t1l
GARNER, NC 27529
PHONE (91 9) 779-4854 Se ►'+� ���.
FAx (91 9) 779-4056
A&H Mine
401 Sand Company
Doc Brown Road
Raeford, NC
Sedimentation & Erosion Control Calculations
TABLE OF CONTENTS
Drainage Area Map_,__ 1.0
Drainage Area 1 _ 2.0
Runoff Volume
Drainage Area 2 _ 3-0
Runoff Volume
Sedimentation Basin 1 Design
Outlet Pipe Design
Outlet Stabilization Design
Diversion Ditches to Sediment Basin 1 Design
Drainage Area 3 4.0
Runoff Volume
Sedimentation Basin 2 Design
Outlet Pipe Design
Outlet Stabilization Design
Diversion Ditch to Sediment Basin 2 Design
Drainage Area 4 5-0
Runoff Volume
Sedimentation Basin 3 Design
Outlet Pipe Design
Outlet Stabilization Design
Diversion Ditches to Sediment Basin 3 Design
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DRAINAGE AREA 1 1 90 5 e a q
21,654 ACRES as 1n "z
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OMNAGE AREA 2
52.5092.5b9 ACRES o
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® DRAINAGE AREA 3
26.838 ACRES r
DRAINAGE AREA 4 193,212 S Feet
15.491 ACRES 9
4.4355 Acres I
DRAINAGE AREA 5 s
4.436 ACRES
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A + �i
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mm 05-28-2Q20
SHEET Na.:
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SCALE: 1"-200'T
H 7 6 5 4 S 2 1
I I I 1
TR-55, 25-Year Storm
401 Sand Mine
Hoke County, NC
Drainage Area 1
Runoff Volume
Q=(P-la)2/((P-la)+S)
Q= accumulated runoff(in.)
P= accumulated rainfall (potential maximum runoff) ('n.)
la intital abstraction including surface storage. interception and infiltration prior to runoff
S= potential maximum soil retention (in.)
Infiltratation for TR-55
la 0.2S
CN for TR-55
CN=10001(10+S)
CN= Curve Number
Soil Type A,
CN= 77 from Runoff Curve Numbers
P= 6.52- in.
A= 21-.654 acres
S= 2.99 in.
la= 0.60 in.
Ia1P= 0.09
Q= 3.94 in.
For Time of Concentration,Tc
T,=(0.007(nL)O B/P20 5SO 4
T,= Time of Concentration
n= �;"Na.Manning's"n"
L= �:52..25-year,
8-Y Flow length, ft.
P25= 24-hour rainfall, (in.)
cw
S= 0ILq .Ground slope, (ft/ft)
Tc= 0.26 Hours
Peak Discharge
Q p=Qt,AQ l'p
Qp Peak Discharge (cfs)
Qu J'50 Unit Peak Discharge for Type II Rainfall (csmlin)
A= 0.034 Drainage Area. (sq. mile)
Q= 3.937 Runoff Depth (in)
Fp= 7r,00 Pond and swamp adjustment factor from Table 2.8
QP 19.98 cfs
1
TR-55, 25-Year Storm
401 Sand Mine
Hoke County, NC
Drainage Area 2
Runoff Volume
Q=(P-la)2/((P-la)+S)
Q= accumulated runoff(in.)
P= accumulated rainfall (potential maximum runoff) (in.)
la intital abstraction including surface storage, interception and infiltration prior to runoff
S= potential maximum soil retention (in.)
Infiltratation for TR-55
la 0.2S
CN for TR-55
CN=10001(10+S)
CN= Curve Number
Soil Type A;
CN= 77 from Runoff Curve Numbers
P= 6:52 in.
A= 52.509 acres
S= 2.99 in.
la= 0.60 in.
la/P= 0.09
Q= 3.94 in.
For Time of Concentration,Tc
Tc=(0.007(nL)0 BIP2 5S0 a
T,,= Time of Concentration
n= D0118 Manning's "n"
L= 3,350 Flow length, ft.
P25= 6.52 25-year, 24-hour rainfall, (in.)
S= 0.019:Ground slope, (ftlft)
Tc= 0.36 Hours
Peak Discharge
QP Q,AQFP
QP= Peak Discharge (cfs)
Q„= 14O Unit Peak Discharge for Type II Rainfall (csmlin)
A= 0.082 Drainage Area, (sq. mile)
Q= 3.937 Runoff Depth (in)
Fp I.Od!Pond and swamp adjustment factor from Table 2.8
Qp 45.22 cfs
Sedimentation Basin Sizing
401 Sand Mine
Hoke County, NC
Sedimentation Basin No. 1
Drainage Area 52.509 Acres
Drainage Area Check Okay
Disturbed Area 52.509 Acres
Discharge 65.20 ftafs Including flow from Drainage Area 1
Minimum Volume Reqd' 94,516 ft'
Minimum Surface Area Reqd' 21,191 ft'
Length 240 ft
Min. Basin Front Width 200 ft
Min. Basin Back Width 100 ft
Depth 4 ft
Side Slopes 2.5 :1. ft/ft
Length[Width Check Okay
Okay
Bottom Length 220 ft
Bottom Front Width 180 ft
Bottom Back Width 80 ft
Top Surface Area 36.000 ft
Bottom Surface Area 28,600 fe
Total Volume 128,891 ft.1
Surface Area Check Okay
Volume Check Okay
Basin Dewatering
Dewater Time 4 days
Flow 32,223 ft31d
Skimmer Size 6 in
Orifice Size 4.442 in
Spillway
Flow Reqd' 64.83 ft31s
Spillway Width 65 ft
Side Slope Ratio 3 :1 ft/ft
Depth 0.5 ft, assumed depth, 0.5 ft max�mum
Velocity 1.95 fUs, less than 2 fUs ideal for peak flow, Q25
Capacity 68.94 ft31s, with a weir coefficient of 3.0 for a broad-crested weir
Riser and Barrel
Flow 65.20 cfs
Diameter 84 in, 15" min, for CMP
Driving Head 1.0-ft, to bottom elevation of spillway
Weir Capacity 65.97 cfs
Capacity Check Okay
Buoyancy Check 10,569 pounds
Anchor Collar Size, Square 12 ft, square, 6 inches thick
Gravity Flow for Pipes
401 Sand Mine
Hoke County, NC
Discharge pipe from SIB 1
Using Manning's Equation..
Q= (1.491n)AR'J3S'!2
Where...
Q = the flow in cubic feet per second (ft31s) or cfs
n = the Manning's roughness coefficient, and n=0.013 is used per regulations
S = Slope(fUft)
R = Hydraulic radius(ft)
A= Cross sectional area of flow(ft)
Use Appendix 16.A in Civil Engineering Reference Manual to find values for A and R
D= 42 Pipe Diameter, in inches
3.5 Pipe Diameter, in feet
So...
A= 9.62 ft2
R = 0.875 ft
S = 0.0056 ft/ft
Q = 76 cfs
33892 gpm
For an inlet control situation only,with respect to the culvert orifice
D= 3.50 Pipe Diameter, in Feet
Cd= 0.60 Coefficient of discharge, dimensionless
A= 9.62 ft2,Cross-sectional area of flow at orifice entrance
g= 32.20 Acceleration of gravity (ftls2)
h= 2.6o ft, Driving head, measured from the centroid of the orifice area to the water surface
Q= 371.86 cfs, Discharge
For culverts with outlet control situation
L= 60,ft, culvert length
dc= 4 ft,
TW= 3.75 ft, tailwater, in relation to pipe diameter
With culvert flowing full, the minimum headwater, HW is
HW= 6ft
H = 2.59 ft, Total head
g = 32.20 Acceleration of gravity (ftls2)
ke= 0.5 Entrance Loss coefficient
n = 0.013 Mannings coefficient
Q = 82.25 cfs, total capacity with outlet control
To determine velocity
V= the velocity of the flow in feet per second (ftls)or fps
n = the Manning's roughness coefficient, and n=0.013 is used per regulations
S = Slope (ft/ft)
R = Hydraulic radius (ft)
So...
S = 0.0056 ft/ft
R = 0.875 ft
V= 7.85 fUs
To determine velocity,flowing at Q2r,
Q25= 65.20 ft'Is, from discharge calculations
0=2(cos 1(1-(yl(D/2))
Q =(1.49In)(D218(0-sin0)(D(0-sin0)140)213
y= depth of flow in pipe, ft
0= the angle of the edges of the surface across the pipe, radians
n = Mannings coefficient, typically 0.013
y= 2.51 ft
n= 0.013
A= 4.04 radians
Q25= 65.20 f13/s, as calculated for pipe flow
Cross-sectional Area of the flow
A=((D218)(0-sing))
R=(D2(0-sino)1(D012))
A= cross-sectional area of the flow at the depth of flow, ft2
R = hydraulic radius of the flow in the pipe, ft
A25= 7.38 W
S = 0.0056 ft/ft
R25 = 1.04 ft
V25= 8.83 fUs
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Sedimentation & Erosion Control Calculations
Diversion Swale Calculations
401 Sand Mine
Hoke County, NC
Diversion Ditch 1-1
Slope of Ditch= HIL
H =The difference in elevation along the ditch in feet
Where: L=The length of the ditch, in feet
So therefore...
H = 18ft
If... L= 850 ft
Slope = 0.02
Solving for depth
Ditch Bottom Width 20 ft
Ditch Side Slope 2 :1 ratio, H:V
Manning's "n" 0.018
Depth 0.30 ft
Discharge 32.60 cfs
Area 6.19 ft,
WP 21.34 ft
H. Radius 0.29 ft
zrey 2.71
zeYg 2.71
Velocity 5.27 ftls
If velocity of flow is greater than 2 tYs, matting is required
Shear Stress: T=yds
T= Shear stress in pounds/fe (psf)
Where y= unit weight of water, 62.4 Ib1ft3 (pcf)
d= flow depth in ft
s= slope of ditch, ft/ft
d = 0.30
Therefore, if: s= 0.02
T= 0.40 psf
Use curled wood matting
Sedimentation & Erosion Control Calculations
Diversion Swale Calculations
401 Sand Mine
Hoke County, NC
Diversion Ditch 1-2
Slope of Ditch = H/L
H = The difference in e..evation along the ditch, in feet
Where- L=The length of the ditch, in feet
So therefore...
Ha 16ft
If L= 500 ft
Slope= 0.03
Solving for depth
Ditch Bottom Width 20 ft
Ditch Side Slope 2 :1 ratio, H:V
Manning's"n' 0.018
Depth 0.18 ft
Discharge 16.30 cfs
Area 356 f:2
WP 20.78 ft
H. Radius 0.17 ft
Zreq 1.10
Zavg 1.10
Velocity 4.58 ft/s
If velocity of flow is greater than 2 ft/s, matting is required
Shear Stress: T=yds
T= Shear stress in pounds/fe (psf)
Where y= unit weight of water, 62.4 Ib/ft3 (pcf)
d flow depth in ft
s = slope of ditch, ft/ft
d = 0."8
Therefore, if, s= 0.03
T;; 0.35 psf
Use curled wood matting
,
Sedimentation & Erosion Control Calculations
Diversion Swale Calculations
401 Sand Mine
Hoke County, NC
Diversion Ditch 1-3
S-ope of Ditch = H/L
H = The difference in elevation along the ditch, in feet
Where: L=The length of the ditch, in feet
So therefore..
H 14ft
If L= 500 ft
S'ope t 0.03
Solving for depth
Ditch Bottom Width 20 ft
Ditch Side Slope 2 :1 ratio, H:V
Manning's"n" 0.018
Depth 0.18 ft
Discharge 16.30 cfs
Area 3.73 ft'
WP 20.82 ft
H. Radius 0.18 ft
zreR 1.18
Zug 1.18
Velocity 4.37 fUs
If velocity of flow is greater than 2 ftls. matting is required
Shear Stress: T=yds
T= Shear stress in pounds/fe (pso
Where y= un`t weight of water, 62.4 Iblft3 (pcf)
d = flow depth in ft
s= slope of ditch, ft/ft
d = 0.18
Therefore, 'f: s = 0.03
T= 0.32 psf
Use curled wood matting
TR-55, 2' -Year Storm
401 Sand: Mine
Hoke County, NC
Drainage Area 3
Runoff Volume
Q=(P-la)2/((P-le)+S)
Q= accumulated runoff(in.)
P= accumulated rainfall (potential maximum runoff) (in.)
V intital abstraction including surface storage, interception and infiltration prior to runoff
S= potential maximum soil retention (in.)
Infiltratation for TR-55
la=0.2S
CN for TR-55
CN=1000/(10+S)
CN= Curve Number
Soil Type- A,
CN= 77 from Runoff Curve Numbers
P= 6.82 in.
A=, 26.838 acres
S= 2.99 in.
la 0.60 in.
I./P= 0.09
Q= 3.94 in.
For Time of Concentration, Tc
T,=(0.007(nL)o a/P2".5S0.4
T,= Time of Concentration
n=` 601.8 Manning's"n"
L= 2,060 Flow length, ft.
P25= 6.52 25-year, 24-hour rainfall, (in.)
S={_ .0.0.16;Ground slope, (ft/ft)
Tr= 0.31 Hours
Peak Discharge
Q,,=Q.,AQF,
Qp Peak Discharge(cfs)
Q„= T'501 Un;t Peak Discharge for Type 11 Rainfall (csmlin)
A=i 0.041, Drainage Area, (sq. mile)
Q= 3.937 Runoff Depth (in)
FP 1.00,Pond and swamp adjustment factor from Table 2.8
Qp 24.21 cfs
Sedimentation Basin Sizing
401 Sand Mine
Hoke County, NC
Sedimentation Basin No. 2
Drainage Area 26.838 Acres
Drainage Area Check Okay
Disturbed Area 26.838 Acres
Discharge 24.21 ft31s
Minimum Volume Reqd' 48,308 ft'
Minimum Surface Area Reqd' 7,869 ft'
Length 230 ft
Min. Basin Front Width 100 ft
Min. Basin Back Width 60 ft
Depth 4 ft
Side Slopes 2.5.:1, ft/ft
LengthlWidth Check Okay
Okay
Bottom Length 210 ft
Bottom Front Width 80 ft
Bottom Back Width 40 ft
Top Surface Area 18,400 ft'
Bottom Surface Area 12,600 ftz
Total Volume 61,505 ft'
Surface Area Check Okay
Volume Check Okay
Basin Dewatering
Dewater Time 4 days
Flow 15,376 ft31d
Skimmer Size 6 in
Orifice Size 3.068 in
Spillway
Flow Reqd' 24.03 ft31s
Spillway Width 30 ft
Side Slope Ratio 3-:1 ftlft
Depth 0.5 ft, assumed depth, 0.5 ft maximum
Velocity 1.53 ft/s, less than 2 ftls ideal for peak flow, Q25
Capacity 31.82 Wls, with a weir coefficient of 3 0 for a broad-crested weir
Riser and Barrel
Flow 24.21 cfs
Diameter 36.in, 15" min. for CMP
Driving Head 1.0 ft, to bottom elevation of spillway
Weir Capacity 28.27 cfs
Capacity Check Okay
Buoyancy Check 1941 pounds
Anchor Collar Size,Square 5 ft, square, 6 inches thick
Gravity Flow for tripes
401 Sand Mine
Hoke County, NC
Discharge pipe from SB 2
Using Manning's Equation._
Q= (1.491n)AR S"
Where...
Q = the flow in cubic feet per second (ft3/s)or cfs
n = the Manning's roughness coefficient, and n=0.013 is used per regulations
S = Slope(ft/ft)
R: Hydraulic radius (ft)
A= Cross sectional area of flow(ft)
Use Appendix 16.A in Civil Engineering Reference Manual to find values for A and R
D= 24 Pipe Diameter, in inches
2 Pipe Diameter, in feet
So...
A= 3,14 ft'
R = 0.5 ft
S = 0.01 ft/ft
Q = 23 cfs
10184 gpm
For an inlet control situation only,with respect to the culvert orifice
D= 2.00 Pipe Diameter, in Feet
Cd= 0.60 Coefficient of discharge, dimensionless
A= 3.14 ft2,Cross-sectional area of flow at orifice entrance
g= 32.20 Acceleration of gravity (ftls2)
h= 1.00 ft, Driving head, measured from the centroid of the orifice area to the water surface
Q= 60.71 cfs, Discharge
For culverts with outlet control situation
L= 60 ft, culvert length
dc= 4,ft,
TW= 3 ft, taiiwater, in relation to pipe diameter
With culvert flowing full, the minimum headwater, HW is
HW= 6.ft
H = 3.60 ft, Total head
g = 32.20 Acceleration of gravity (f/S2)
Ice= 0.5 Entrance Loss coefficient
n = 0.013 Mannings coefficient
Q = 26.99 cfs, total capacity with outlet control
To determine velocity
V=the velocity of the flow in feet per second (ft/s)or fps
n = the Manning's roughness coefficient, and n=0.013 is used per regulations
S = Slope (ft/ft)
R = Hydraulic radius (ft)
So...
S = 0.01 ftlft
R = 0.5 ft
V= 7.22 fVs
To determine velocity, flowing at Q255
Q25 = 24.21 ftsls, from discharge calculations
0 = 2(cos`1(1-(yl(D12))
Q =(1.491n)(D2/8(0-sin6)(D(0-sin0)140)2!3
y= depth of flow in pipe, ft
0 = the angle of the edges of the surface across the pipe, radians
n = Mannings coefficient, typically 0.013
y= 1.81 ft
n= 0.013
9= 5.02 radians
Q25= 24.21 fl'Is, as calculated for pipe flow
r
i
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A=((D218)(0-sin@))
R=(D2(0-sin0)1(D012))
A= cross-sectional area of the flow at the depth of flow,ft2
R= hydraulic radius of the flow in the pipe, ft
A25= 2.99 ft`
S = 0.01 ftlft
R25= 0.60 ft
V25 = 8.11 fUs
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Sedimentation & Erosion Control Calculations
Diversion Swale Calculations
401 Sand Mine
Hoke County, NC
Diversion Ditch to Basin 2
Slope of Ditch = H/L
Where'. H =The difference in elevation along the ditch, in feet
L=The length of the ditch, in feet
So therefore...
If... H= 12 ft
L= 1540 ft
S'ope= 0.01
So'ving for depth
Ditch Bottom Width 10 ft
Ditch Side Slope 2 A ratio. H.V
Manning's"n" 0,018
Depth U1 ft
Discharge 24.21 cfs
Area 5.60 ft'
WP 12.27 ft
H. Radius 0.46 ft
zreq 3.31
zavg 3.31
Velocity 4.33 ftls
If velocity of flow is greater than 2 ftls, matting is required
Shear Stress; T=yds
Where T= Shear stress in pounds/ftz (psf)
y= unit weight of water, 62.4 Ib/ft3 (pcf)
d = flow depth in ft
s= slope of ditch, ft/ft
Therefore, if: d = 0.51
s = 0.01
T= 0.25 psf
Use curled wood matting
TR-55, 25-Year Storm
401 Sand Mine
Hoke County, NC
Drainage Area 4
Runoff Volume
Q=(P-la)2/((P-18)+S)
Q= accumulated runoff(in,)
P= accumulated rainfall (potential maximum runoff) (in )
la intital abstraction including surface storage, interception and infiltration prior to runoff
S= potential maximum soil retention (in.)
Infiltratation for TR-55
Ia70.2S
CN for TR-55
CN=10001(10+S)
CN= Curve Number
Soil Type k
CN= 77_from Runoff Curve Numbers
P=. 6.52 in.
A= 14 .490 acres
S= 2.99 in.
la= 0.60 in.
IJP= 0.09
Q= 3.94 in.
For Time of Concentration,Tc
T,=(0.007(nQ"5'P+o.Ss0 4
T,= Time of Concentraton
n= b.bi5,Manning's"n"
L= 2,460:Flow length, ft.
P25" 5-.52-25-year, 24-hour rainfall, (in,)
S= 0111149)Ground slope, (fVft)
Tc= 0.28 Flours
Peak Discharge
Q�TQwAQFp
Qp= Peak Discharge (cfs)
QU=` 1501 Unit Peak Discharge for Type II Rainfall (csmlin)
A= 0.024 Drainage Area, (sq. mile)
Q= 3.937 Runoff Depth (in)
Fp r 1.00 Pond and swamp adjustment factor from Table 2.8
Qp= 14.29 cfs
Sedimentation Basin Sizing
401 Sand Mine
Hoke County, NC
Sedimentation Basin No. 3
Drainage Area 15.49 Acres
Drainage Area Check Okay
Disturbed Area 22.67 Acres
Discharge 14.29 W s
Minimum Volume Reqd' 40,806 W
Minimum Surface Area Reqd' 4,645 ft2
Length 160 ft
Min. Basin Front Width 80 ft
Min. Basin Back Width 80 ft
Depth 4 ft
Side Slopes 2.5 :'.. ft}ft
LengthNVidth Check Okay
Okay
Bottom Length 140 ft
Bottom Front Width 60 ft
Bottom Back Width 60 ft
Top Surface Area 12,800 ft2
Bottom Surface Area 8,400 ft2
Total Volume 41.867 W
Surface Area Check Okay
Volume Check Okay
Basin Dewatering
❑ewater Time 4 days
Flow 10,467 ft'/d
Skimmer Size 6 in
Orifice Size 2.531 in
Spillway
Flow Reqd' 14.17 ft'ls
Spillway Width 20 ft
Side Slope Ratio 3 :1 ftlft
Depth 0.5 ft, assumed depth, 0.5 ft maximum
Velocity 1.32 fUs, less than 2 ftts ideal for peak flow, Q25
Capacity 21.21 Wls, with a weir coefficient of 3.0 for a broad-crested weir
Riser and Barrel
Flow 14.29 cis
Diameter 30 in, 15"min. for CMP
Driving Head 1.0 ft, to bottom elevation of spillway
Weir Capacity 23.56 cfs
Capacity Check Okay
Buoyancy Check 1346 pounds
Anchor Collar Size, Square 4 ft, square, 6 inches thick
Gravity Flow for Pipes
401 Sand Mine
Hoke County, NC
Discharge pipe from SIB 3
Using Manning's Equation..
Q= (1.49/n)AR213SN2
Where...
Q=the flow in cubic feet per second (ft3/s) or cfs
n =the Manning's roughness coefficient, and n=0.013 is used per regulations
S = Slope (ftlft)
R= Hydraulic radius (ft)
A= Cross sectional area of flow(ft)
Use Appendix 16.A in Civil Engineering Reference Manual to find values for A and R
D= 18 Pipe Diameter, in inches
1.5 Pipe Diameter, in feet
So...
A= 1.77 ftZ
R= 0.375 ft
S = 0.02 ft/ft
Q= 15 cfs
6687 gpm
For an inlet control situation only, with respect to the culvert orifice
D= 1.50 Pipe Diameter, in Feet
Cd= 0.60 Coefficient of discharge, dimensionless
A= 1.77 ftZ,Cross-sectional area of flow at orifice entrance
g= 32.20 Acceleration of gravity(ft/s2)
h= 1.00 ft, Driving head, measured from the centroid of the orifice area to the water surface
Q= 34.15 cfs, Discharge
For culverts with outlet control situation (NOT APPLICABLE)
L�, ft, culvert length
dv ft,
TW vt 0.75 ft, tailwater, in relation to pipe diameter
With culvert flowing full, the minimum headwater, HW is
HW= ft
H = -0.75 ft, Total head
g 32.20 Acceleration of gravity (ftlsZ)
ke= Entrance Loss coefficient
n = 0.013 Mannings coefficient
Q = #NUM! cfs, total capacity with outlet control
To determine velocity
V= the velocity of the flow in feet per second (ftls)or fps
n = the Manning's roughness coefficient, and n=0.013 is used per regulations
S = Slope(ft/ft)
R= Hydraulic radius (ft)
So...
S = 0.02 tuft
R = 0.375 ft
V= 8.43 ftls
To determine velocity,flowing at Q25
Q25= 14.29 ft'Is, from discharge calculations
0 =2(cos 1(1-(yl(D12))
Q =(1.491n)(D2/8(0»sin0)(D(6-sin0)140)2j3
y= depth of flow in pipe, ft
0 = the angle of the edges of the surface across the pipe, radians
n = Mannings coefficient, typically 0.013
y= 1.18 ft
n= 0.013
0= 4.36 radians
Q25= 14.29 ft31s, as calculated for pipe flow
t ,
Crass-sectional Area of the flow
A=((D2/8)(0-sin0))
R=(D2(0-sin0)I(D012))
A= cross-sectional area of the flow at the depth of flow, ft`
R = hydraulic radius of the flow in the pipe, ft
A25 = 1.49 ft2
S = 0.02 ft/ft
R25= 0.46 ft
V25 = 9.60 fUs
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Sedimentation & Erosion Control Calculations
Diversion Swale Calculations
401 Sand Mine
Hoke County, NC
Diversion Ditch 3-1
Slope of Ditch= HIL
Where: H � The difference in a;evation along the ditch, in feet
L=The length of the ditch: in feet
So therefore,,,
If... H 6 ft
L= 260 ft
Slope i 0.023
Solving for depth
Ditch Bottom Width 1fl ft
Ditch Side Slope 2.:1 rato, H;V
Manning's"n" 0.018
Depth 6.10 ft
Discharge 7.15 cfs
Area 1.84 ft�
Wp 10.80 ft
H. Radius 0.17 ft
zfeq 0.57
zava 057
Velocity 3.88 ftls
If velocity of flow is greater than 2 ftls, matting is required
Shear Stress- T=yds
Where T= Shear stress in poundslft2(psf)
y= unit weight of water, 62.4 lblft3 (pcf)
d= flow depth in ft
s= slope of ditch, ftlft
Therefore, if: d = 0.18
s= 0.02
T= 0.26 psf
Use curled wood matting
a 1
Sedimentation & Erosion Control Calculations
Diversion Swale Calculations
401 Sand Mine
Hoke County, NC
Diversion Ditch 3-2
Slope of Ditch= H/L
Where: H= The difference in elevation along the ditch_ in feet
L=The length of the ditch, in feet
So therefore...
If. . H = 4 ft
L= 320 ft
Slope:;; 0.013
Solving for depth
Ditch Bottom Width 10 ft
Ditch Side Slope 2 :1 ratio, H:V
Manning's"n" 0.018
Depth 0.32 ft
Discharge 14.29 cfs
Area 3.44 fe
WP 11.44 ft
H. Radius 0.30 ft
z,.Qq 1.54
z81g 1.54
Velocity 4.16 ftls
If velocity of flow is greater than 2 ftts, matting is required
Shear Stress: T=yds
Where T= Shear stress in pounds/ft? (psf)
y= unit weight of water, 62.4 Iblft3 (pcf)
d =flow depth in ft
s = slope of ditch, ft/ft
Therefore, if: d= 0.32
s= 0.01
T= 0.25 psf
Use curled wood matt:ng