HomeMy WebLinkAbout19970694 Ver 1_Stormwater Info_20020304200?.
THE JOHN R. WADAMS COMPANY, INC.
LETTER OF TRANSMITTAL
To: Todd St. John
Date: March 1, 2002
Division of Water Quality
Environmental Sciences Branch
4401 Reedy Creek Rd.
Raleigh, North Carolina 27607
Re: The Gardens at Wakefield Job No.
Sand Filter Design Calculations
I am sending you the following item(s):
** FEDERAL EXPRESS **
FCC-01000
COPIES DATE NO. DESCRIPTION
3 3 Sand Filter Design Calculations
3 3 Sand Filter and Site Plans and Details
These are transmitted as checked below:
? As requested
® For approval
? For review and comment
Remarks:
? For your use
Copy to: Mike Munn, P.E. Signed:
FOR INTERNAL USE ONLY
® Copy Letter of Transmittal Only to File
? Copy Entire Document to File
CIVIL ENGINEERING • LAND PLANNING • SURVEYING
PO Box 14005 • Research Triangle Park, NC 27709 • (919) 361-5000 • fax (919) 361-2269
www.johnrrncadams.com
QUALPOND.XLS
Sand Filter
FCC-01000
Water Qualitv Pond Desian Sheet
Project Name: THE GARDENS AT WAKEFIELD
Designer: J. E. Schrum, E.I.
Job Number: FCC-01000
Date: 1/25/02
Ks = 3244.8
b = 1.3769
Calculation of Runoff Volume required for storage
The runoff to the pond for the 1" storm detention requirement is calculated using the SCS curve
number method. Impervious areas that directly enter the pond are counted as Directly Connected
Impervious Areas (DCIAs). No infiltration calculation will be provided for these areas. Areas
not directly connected will be accounted for in a composite curve number.
From SCS Soils Survey map, predominant hydrologic soil type = B
Using basic SCS runoff methodology, with no ac
to initial abstractions (0.2*S and 0.8*S).
Impervious Area, directly connected (DCIA) _
@CN=
Other areas draining to pond (not DCIA) _
@CN=
Runoff from DCIAs =_>
Ijustments made
2.15 acres
98
2.09 acres
61
Precipitation amount = 1.0 inches
S = 0.204 inches (calculated)
Q* = 0.791 inches (calculated)
Runoff volume = 6173 CF
Runoff from non-connected areas =_>
Precipitation amount = 1.0 inches
S = 6.393 inches (calculated)
Q* = 0.000 inches (calculated)
Runoff volume = 0 CF
Therefore, total runoff from precipitation in question = 6173 CF
This amount of runoff must be stored in the pond above normal pool elevation,
and be released in a period of two (2) to five (5) days, by an inverted PVC
siphon, the invert end of which is set at permanent pool elevation.
J.E. SCHRUM, E.I.
Page 1
STAGE-STORAGE.XLS
SAND FILTER
FCC-01000
Stage-Storage Function
a„
Average Incremental Accumulated Estimated
Contour Contour Contour Contour Stage
Contour Stage Area Area Volume Volume w/ S-S Fxn
(feet) . (feet) (SF) (SF) (CF) (CF) (feet)
288.0 0.0 3500
290.0 2.0 5080 4290 8580 8580 2.03
292.0 4.0 7323 6202 12403 20983 3.88
294.0 6.0 9742 8533 17065 38048 5.98
295.0 7.0 11028 10385 10385 48433 7.13
Storage vs. Stage
60000
50000
40000 y = 3244.8X''3759
R2 = 0.9985
30000
m
0
N 20000
10000-
0
L0.0 2.0 4.0 6.0 8.0
Stage (feet)
KS = 3244.8
b = 1.3759
J.E. SCHRUM, E.I.
1/25/02
1 OF I
QUALPOND.XLS
Sand Filter
FCC-01000
Calculation of depth required for runoff storage pool (above normal pool)
Normal pool depth (above invert) = 0.00 feet
Storage provided at permanent pool depth = 0 CF (calculated)
Total storage required for normal + storage pool = 6173 CF
Stage (above invert) associated with this storage = 1.60 feet
1 Therefore, depth required above normal pool for storm storage = 1.60 feet
19.15 inches
J.E. SCHRUM, E.I.
Therefore set crest of principal spillway at stage = 5.00 feet (Note: crest elevation is set based upon the
and EL = 293.00 feet detention aspect of the sand filter.)
At principal spillway crest, storm pool storage provided = 29710 CF
Page 2
sand filter drawdown.xis
Sand Filter
FCC-01000
«.> Sand Filter Drain Pipe Design Sheet
I
' D siphon = 6 inches
No. siphons =
II 1
.
Ks = 3244.8
b= 1.3759
_
Cd siphon = 0.60
Siphon Invert = 286.50 feet
Volume @ Normal Pool = 0 CF.
Basin Invert = 288.00 feet
WSEL
(feet) Vol. Remaining
c Siphon Flow
cfs Avg. Flow
cfs Incr. Vol.
c Incr. Time
sec
289.900 7847 1.675
289.746 6984 1.634 1.655 863.8 522.1
289.591 6148 1.591 1.612 835.5 518.2
289.437 5343 1.547 1.569 805.6 513.4
289.282 4569 1.502 1.525 773.6 507.4
289.128 3830 1.456 1.479 739.3 499.9
288.974 3127 1.408 1.432 702.1 490.5
288.819 2466 1.358 1.383 661.4 478.3
288.665 1850 1.306 1.332 615.9 462.4
288.510 1286 1.252 1.279 564.1 440.9
288.356 783 1.196 1.224 502.7 410.6
Drawdown Time = 0.06 days
By comparison, if calculated by the average head over the orifice (assuming
average head is half the total depth), the result would be:
Average driving head on orifice = 1.450 feet
Orifice composite loss coefficient = 0.600
X-Sectional area of 1 - 6" inverted siphon = 0.196 ft2
Q = 1.1384 cfs
Drawdown Time = Volume / Flowrate / 86400 (sec/day)
Drawdown Time = 0.08 days
Conclusion : Use 1 - 6" Diameter PVC drain pipe to drawdown the accumulated
volume from the 1.0 " storm runoff, with a required time of about 0.07 days
Therefore, the pipe will not constrain the drainage of the sand media.
J.E. SCHRUM, E.I.
1/25/02
SIPHONS.XLS
sand filter drawdown.xls
Sand Filter
FCC-01000
Drainage through the Sand Media:
J.E. SCHRUM, E.I.
1/25/02
Per NC DENR DWQ, the sand to be used in the filter is to be less than 2 mm in average diameter.
DWQ assumes this sand to have a permeability of 0.04 gal/min/SF (with 1 foot of head over the sand surface).
Average depth of water over sand surface (1/2 maximum depth) = 0.95 feet
The DWQ assumption for sand permeability will be used.
Calculation of drawdown time through the sand =>
Surface area of horizontal sand surface = 1758 SF
Assumed permeability of sand = 0.04 gal/min/SF
Volume stored during storm of interest = 7847 CF
Time required to drawdown through the sand media = 0.58 days
In this case, the sand media is the restricting factor, resulting in a drawdown time
of 0.58 days (13.9 hours). This is within the DW4 requirement that requires the sand filter
drained within a 24 hour time period.
SIPHONS.XLS
i
II
CA
o
c ?
n
O. N
E (L)
0 Z
N 'L
E to
a
? '0 N
' LO C
04 (D
lL O
M ~
c X t
02
m N
. m
N
3 0
o
0 $
CL I °
m . W
I ?
13
C
C
!6
f
o E
o E
_ o
A ?
J _ v
m
T o
y N
O
0 0 0 0 0 0 0°
C W C
Cl) °N N -
($40) Mow
m N _
c m e m 0 m
°ooo o o°o Co °a o o°o-oo
.-06M0O(o(V O(M
O N r N 0 0 N
II
zw
o O O
'000
?- 11 11
m II v
?JNU
Z 11 t N
0 1`p v C II W
W m > J
W p m 11 11 11 If 11
LL z
Y p?ZOUN0 0 00 00 00 00
Z.
W
N `N Z CO 0)
W W. mm?a3UU
0o ~ O?COOMtiN O
J
? ON LL N W OO vi r- co co
N to
(? O 0 m w N N m m
3 M 7 7
•6 = U N W Q A C C N m ? c C
0F-IL? ?(n UEE w m UEE
m I- I- O Goco0 o Loo
6 4 ?NNN Cj co ..CMO c c
p1 O N N t?l 11 O
C CL M O W 11 11 O.
O Cf J m Q NO 11 'o
O dj O
O
E .. Q w t 11 N p LL IT
O
RZ :: w ea .4+N?msT ?(0 c tt o m 3 n m?waOH m Of
LM L E
to.o?'a?i ?.lo - ow Av111 to ±au Oo0mmmawi o aIQ•CL
t?aaa SCJF- v fgY flN SN Uz2aaIT a SC'!f o
` OrMtOO?CO
m 00000 r.-
m R
N
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0-4
U
OoooOOo
N 0 0 0 0 0 0 0
,. 0000000
w
oOOOOOa
0 0 0 0 0 0 0
r O O O O O O G
rrO(OMtA
O O O O O M
r to to 0i t1i000
C? rr-r?NNN
m 3U w
F
M C9 W? CO M O Il?
C CA to tJ) 0 0" O -
r
mU?
S
q M UA CCR MAN
00m CA 00?
? c
w Cl 0 0 0 Cl 0 0
O 0 0 0 0 0 0 0
?
m w
a?
` OOOOOOO
CD ooOOO0
m 0000000
3 ?
? w
0 0 0 0 Cl 0 0
0 0 0 0 0 Cl 0
O 0 0 0 0 0 0 0
3
O
OOOrM1A f?
m O CC-0 zol z z
m+ N N N N N N N
N
OOr1?O V M
G? OOOh NCO 1:
NM et°'3cl)O
r •- N
to
OCOM 00(OCn
3 CEO-N't1 0
O ?tlF/
C w
m
E
H
O O
O N
Xdl
CA
C
.j
O
V
.N
CS
N O n n t` LA N M t- LA M r O M M r`(0 W LOV; V M M N N N N r r r r r r r ra-0 0 0 0 0
mN (V (.IN(V (V (V rr r re-.-000iCCOOCCOCCG000000000000000
to
l?6
CL Z
m R
N
O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 OO O O O
V 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 C 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
N 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 C
0 0 0 0 0 0 0 0 0 0 0 0 O.O O O O O O O O O O O O O O O O O O O O O O O O O O O O
` O O O O C 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
3
LArr NMMO(Or r v Nr-MMMO(0 NOa0(OLAMrOMtl- (0W V•MNrrOMM
OL M MLA r h M M V' M f,.-: O M to t*-: M M O M ? M M CD 00 OR OR OR OR I, t? f: i, ?? h h h r,.: F: q
4 a+?r N MC! A V wow 0r-t-nf- r• t` w r*r.r.t.r?r?r?r?r?hhht?hl?hl?hi?hl?l?h
?CL+ O N N N N N N N N N N N N N N N N N (V N N N N N N N N N N N N N N N N N N N N N N N
m U ,
F
N Mr- IT M M LA m0 M LA LO O O(O MO O W LAN O W LA Mr M W 0 W M Nr MOO fl- (O LA M?
OLAMNrMt`MNMMOON(OM7M V V' V clgq MNNNNrrrrrrr000000
wNM V' LA LO CO ti CO OO M O) O 00- -r a- rr r r r -- rf- r r r e- rr
m O r r r r r r r r r r r N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
mV
S
?MNMi M LLO Nap MOMONf000w M0V - 0 MMtN00NN. . . . .M?r00000000
0 NM V 0LO W r-W OOM M 0 o 0 r- a --- -r -- a- rrrr
L r r- r c- r r r r r r r- N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
O (Q
F, m
N .
LL "'-OOOOOOOOOOOOOONLAMOOI?LA Me? N ??{{OrCO(OMh OOMN??}}OMr (Doll
(n vw0000000000000O.r- NCOrM Ot0Na0LON0)fl- W V: M M (MM V; V;(Olh
0 OGO000000C0000 LO W O O O 0 r'. (oV'CO r 00) ti CO LA A MN r O M 00 1,- to q) LA
M V' LA LA LA V' V• V' d• V' V• M M M M M M M M N N N N N N
L
m
N_
0 0 0 0 0 0 0 0 0 O.O O O O t? N (O M r aD O V' N V' 0 0 e? ? ? 0 00 00 0 V' M (O M N N M
0 0 0 0 0 0 0 0 0 0 0 0 0 0 CO M V' I? V' W M t? N 1? M MLA N M V' r M 00 (0 V' M N r O M
300000000000ooo(q u5 1-r?r-0(ULO0V ;r mm MNNNN - rr -r--- --0
i
m
0 0 0 0 0 0 0 0 O O O O O O ? N 0M r M0vN V'0 0 re? OOOMO V'M COM NNM
00000000000000COM V'I- V:OO(O t?Nhmo) 0) V 0)C0 CO V; CMN rOM
r?-rrrr?--r
000000000000000NLAr-r,? t,? co(ou) Lpv V:vi mmN(V (V (V 0
3
0
O(MI?O V'CO7LAGO7 V'(OOOOrMMMMMMNNNNNNNNrrrrrrrrr
WCACA000CV NN(V('MM('7MMMMOM CO COM M(M CM COM(MMMM('M ('M CMMMMOMM
m 00 00 00 M M M M M M M M M M M M M M O M M M M M M M M M M M M M M M M M M M M M M M
? N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
O
M n CD MNN IT OOM pl? i?r MRMOM LA(o Co LA O N LA M r 001000 LA O N P,.: N LA.. N r C0
mONN(M(7 r V'OMLAMMOC O(?MOO r?r O0 r-V' Lp V'O MOM V'OCM00O0
MO )o O tO M ? NCO COLD M CO O rN f?N00r M(OM ?I- hI-00MrM(00 00
e? MOOMapV'O
(6r ti-tO 000 Nf?rtA r`t` LO Mr(p MIS r MOO t-(0 V'M NrO(0110 C0 r?1?(O tO LO V'() CO (O
OM V' CO CD O M LO M N N N CO N N 0MM04 ----- OO 01'-0 M C U3 M M M 0(00
Y r r r r
LO ONMr(0 LA O0 V' CO M LA r M 0000 M r V' M N ti N OR t} r M LAN O OO(O Ln M N r O M M? CO
. .. . . . . .
NLAhaO000M00t0 V'MNOMCOhI- (OLA1A V V'MMMNNNNrrrrrrr0000
O r r r r N N N .r r r r r r r
w
C
O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O
. . . . . . . V.. . . . . . . . . . . . c? . . . .
'd'(OOOON'Lt(U000N V'COCOON (OV Od'LOtNALApLO A (0 0 (NO 0 (0 (0 0 ntitit- ?OOD00000CCOOODD00) 00)
?rrr N N N N N M Cl) Cl) Cl) It A V'
H
N
X
M
c
O
U
r
_O
LL0)
O
c
m
N
a
Z
U U)
E
a
? lT
O C
O ,C
C X U
0? m m
L 0 m
F-a:W
0
0
o g
O
C ?
0 o
co
•p C
o E
$ o
C f? E
O ?
J ?_ o
O
N
O
0
0 0 0 0 0 0 0
M N N ' O 6 O
NO) -Ij
m m
C w t w w
000000)00(MO
0 0 0 0 0 10 0 0 r O
r 0 m606 06 CV O6
(D Nr NOON
11 it
000
qq
0. O 0
N
? II II
mfl ?3
?..JNU
Z II t m
0 m vs, W
W m J
W o e 11 II 11 II II
Li z q ?av (`om (o `m
Y Ow z U O N C O M M M M
z
W
w co CO)
0 0 Q1 N LL LL M
z 0: m m -4)5 L)
r
K
Ill 11i
R CO J O M V O N N 0
Q?N U.. H N O r M 6LoP N y N
C900 cl
4: .0.. OON rr M .0.. 4:
W U U z U M U>
'O=UN W Q LL._._ d d LL C C
0 E- IL r -? CQ U E E (D w U E E
m „01.0 co Goo 0 vI- o
CNNN tt?-000 0 0 0 •• 'pM sf N
C N
O
O a M N > N ? m 11 11 O.
O N II
O y cm J m Q N 11 11 O$
E .. t m tQ LL FL T c
3 m G OO ?, p O 0 O_ O p
10 Z C pLa 2 02 5CDE La
= O N 6f
c m m p/.. O m C min WCn?I- E O
11 If Offl 11 It
11
•? •? m ' N 'p fl 'am-_. lY0 N N (Y6 0 'p 11 It
L10 m y m= >,. n Q H. 2,11 O Oct (x6 0 0 0 0 0 !. Q tz. F-
t?aaoof- xa (AY ON 5nl 0z?0- n.0- 0-
> xc7i-v
` Or N"C OR N(O r
000 Cr•C r
" - .
1U.
m 19
l00
co
0 0 0 0 0 0 CO 0
0 0 0 0 0 0 0 0
0700000 C?0
w A
O,
V
00000o00
N 0 0 0 0 0 0 0 0
` C O C 0 0 0 0 0
C)
0 0 0 0 0 0 0 0
L
3 O
rr OONin hn
O CO CO CO OO r ? O t0
O O N N N N
m (? O
NCO MC-A
MM(C)CA'NOO
0(A Oi (AO rCV
fn Of rr
x
(C)IOMN OEM M'N
MMCq to V NOO
`? (310>Oi [A O?CV
r r
m
0 0 0 0 0 Cl 0 0
0 0 0 0 0 0 0 0
0 CO 0 0 0 0 0 0
O
m C>!
f1'
` 00000000
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
m
0 0 0 0 0 0 0 0
0 0 0 0 0 0 C. 0
C O 0 0 0 0 0 0 0
O
OOON M (0O N
Cit co Go OC co OD co OCI O
O OOOOOOwww
NNNNNNNN
O O ?t CA M (O CO 00
M
CQ OOU') 't co m0
C*4 (D to
$ r cm V
O It P.: CO NN Cn 00
OOrMtpONln
O r r
C
0 0 0 0 0 0 0
O O CV 4 (O co C> C*NJ
E-
H
N
X
C6
c
U
Q
41 6)rM V V Mr (OtpN0ORgU( CrlNr06)COf*- q q nUn It It CMMMNN...7 777
?' CV NCMMMCMMCOCV CV CV CV ?"?-'t"'ra-%s=rCCO00CO00000000COOC000
't7 V
C
t0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
00000000000000000000000000000000000000000
mooooooociooooo00000000000000ooooocooooccoo
m ..
? R
O?
V
O
LL
M
00000000000o00000000000000000000000000000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
N 0 0 0 0 0 0 0 0 00 0 0 C >O 0 0 0 0 0 0 O CI 0 0 0 0 C>40 0 0 0 00 0 0 0 0 0 0 00
°
°
°O
°
°
°
°
°°°
00°
°
°
°°°
°
°°°
°
°
°
°
°
°
°
°
°°°
°
°
°
°
°
°
°
°
o
oo
o
oo
O
o
0
0
0
0
00
0
00
0
0
00
0
0
0
0
00
000
0
0
0
0
00
0
0
0
`"? ooooo00oooo0ciooocooooo00000000ooooococooo
$J
NrNNr(O nNOM(M(M CM 0 W M MW M co W w M?--M r- to M N 0 0 O0 to V MNNr00
O MO1?et'-h(I O 'It CO r N N N r r O O O O g q()? O CO OO 00 aq CO CO I: f-: fl? hf? t" h; <O
CV V)MAtf)0(0(0 n h CD CO O CO CO M CD CD M CD t- t`r- t`t+t- tit- t- r- nr- t`t`hht-t+t•nt-
N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
V
O O?NNtO NOOr h to O CO r ti M O O (N 6)(O M Co CO CO V N O 00 (D M(M Nr 06) CO n CO(()
-
006)0 CO(Od:rhN tn(O(O(O(O to U( ? q1t It q M M M N N N NNrrr?r?e
00000
C ------- N N
N
N N N
N N N N
N N
yj
U ? N
N N N
N N N N N N N N
N N N N N N N N
N N
v
O O)hN Nth N O Or ? M 00 hM6)tO N 6)(O M O CO CO It N O 00 (0 LO Cr) NrO O CO h(O to
Oa! qO OR (P cj r t'N Uq C0 (O CO CO (n Un?? q1t q v! M q N N N N Nrr e-rrr00000
L ems' Mr N N N N N N N N N N N N N. N N N N N N N N N N N N N N N N N N N N
?
m
C) C, M M
W
N r- 10
N
?
OOOOOO
rn
9
0
V
°
N
N
°
0
0
r
w tUn Iq
t
O
u
n
a7 CO t6 U
tn(O
6)
O
OOt
A N
i
ceO
C
OO V
r- V
rn
C OOOOOOOOO(TCO(MMN0WW t[) M to CACD(O et MN00W0tnV MN C MW t- W
M16 W0 O(O to LO to st V'st <t st CO ctMMMMMMMM N N N NN
?
?
m
` O O O O O O O O O CO f- O N O CO I- CO LO V CO O) CO MM CO t• O t- t` 0) NN(M IAN OO CO V V
OOOOOOOOOer t
rNN6)
(OtAMNrq
CO ID
?
V UD MCO M 6)(O N 6)(O NO C
y ?
?
h
R
ti
000000000CMr tri tO '4- (V ?OtAOf- t- t0 t(i W) sr sr MCMMN(V NNNrrrrrrr
r r r r r r
m
Mo
?
eV{
O
OOOMCMOM
((
OOOOOOOOO V II?NNMtti(OO(OO? 0)?
~
C%
M
NOCM
(OtN0(O)N?0
O 6
)
I
(
O
D
O ?t
9t
000000000 r)
0Lo vci
O 6)o r`I-? (O ui to V V 6 MMNNNC"i c,4 e-r z
-
-
r r r r
O
1170 VCOMhrtfl (AN V tp t(7 V V V V MMMMMNNNNNNN N r r r r r r r r r rr
. . . . . . . . . . . .
. . . . . .
.
. .
.
m .
. . .
. .
. . .
O O O O r r N N N M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M
Q! N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
?
MO V O(O(OM0000)rMhng gcq 0MO V t?rOt`t-MOCMONCOtOgCO V R70CD V
m
O) 0(n tAMOCO CA fMOMOO)1!'/ (V CA C?h O(O fM?OCO V <TNNa000)N.- V CV 00?
i?tC)
?
M ?
rCOhMt?CD CO t? tp tArNN6)CO COON(Orf?Mr0a1 <TO N(OOrO
COs OO
tArh(p (6h0000r0f0 (O NOI?IA VN06)I?(O tAMNr000CptinO(A V V'MM
(n C00(0) (0 0)
O
M
Cl)CM
--
N
0000
NNNMN C
M MM
NN C
M MMMMMMM
M MMMC
MMMCM
N
6) (O CO M O CO O r O CO O N P,: CM r O O r q O Q) M CO M O U7 r CD (n M r g n O M N r 0 0 CD h
. . . . . . . .
3
C N N N N N N N N- O O M N r O 0 co 0 O 1n . V V M M M N N N N r r r r r r r 0 0 0
r r r r r r
C t)
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
(O CO ON V CO 000 CV It Co D 0 N CO CDO(V t(OCOONcc}?Co000fV d'tOCOONd'COCOOCV ?'(O
rr NNNNNCMMMMCM V V V V Looi7wow(O CO COCOt-tl- ? CO CO O O CO O)6) 06)
e
E
H
N
X
(7)
C
3
O
U
a'
}
O
O
LL
U
0
T ?
C A
Q N
U Z
N ?
E
a
N
O al
O C
O
C X L
L O 2
-0m
4)0
m
Paa
L ++ L
C ql C w w w
0000000000m0000?°0
?O ri M OO O co CV ol,:
O a)- NOON
Z II 'G 'm
? ? m C 11 w
I 9 Wm ?J=
w om „11 II II 11 .
Z ?3:Z3.0 m?ac`o
Y ptYZOUNOUmo000m
Z
H H
m m CO LL
w W m m m m U U
DfO J 00 VO_'ONO n
QoN U. N to 0008) OMa N
.m.
O O O > > N VN
LLIUNUZ P
13 m LL C C m m
01-LL (n a E E w w
co to o co co Cl 0
'O CM N(V d'M 00 CG
='-T N P,4 N 00 ••00 N II
C C. .. j N 11 11 11
7
O N ` Q. m It 3 0 m
E .. 01 t Q tt m LL
O
NZ •? r0? m W In
c ? o m c mv?win01° 'E
4) 4)
O "O' w m it 11 11 m 11 11 a+ 11 X N YN lY6 N 7
•? O
a.aDDP =t11°? ?Y o ER c°?z2aaa.o-
m m
R42
000
N
_L 11 11
rou ci3
?JNU
00000000
N 0 0 0 0 0 0 0 0
?L 0 0 0 0 (D 0 0 0
T
0 0 0 0 0 0 Cl 0
0 0 0 0 0 0 0 0
0 0 0 0 00 40 0
o ??ontic`?vCO
0
o OD 00 0)0) o c%i v.v
mU v
was
O U') O tl t.- Co M O
?O CO COON`- " IA 00
U i r
OORR
w w00)ONco
m
w 0 Co 0 0 0 0 0 0
0c'
O 0 0 0 0 0 0 0 40
m t1
_M
00000000
L o0000o00
3 00000000
m
0 0 0 0 0 0 0 Co
Co 0 0 0 0 0 0 0
O 0 0 0 0 0 0 0 co
0
Off. NNNNNNNN
a?
0 Co 0 0 v v 0 N
W 00000))toN ??
M V'M000)OD
O a-N It l-
OMONN 000)
3 00(h t?N? ?NN
C
0 0 0 0 0 0 0 0
? OCV sr <G 00C??
?E
E"
y
X
O!
C
O
U
M)
N
Q
D:
}
O
O
LL
°
°
°
°
°
°
°
°
°
°
°
°
°
°
°O
°o°
°
°O
°
°
°
°
°
°
°
°
°
°
°
°
°°°
°
°
°°
°
°
°
o
o
o
o
o
o
o o
o
o
o
o
o
a
o
OO
o
o
O
o
o
o
o
o
o
o
o
o
o
o
oo
o
o
oo
o
o
o
N 0 0 0 0 0 0 0 0 0 0 0 O 0 0 0 0 0 0 0 0 0 0 0 0 C O C C O C G 6 C O O C O 6 0 0 C
t7
00
O O O O O O O O O O O O O O O O O O O
O O
O O O
O O
O O
O O O O O O
O
O O O
O
0 0 0 O O O 0 O O O O 0 0 0 0 0 0 0 0 0 0 O G c; C C O C 6 0 0 0 C C 0 Otj O O C C
3 O
O NUONOhON(O0 V-"MMIDr-0 s}?ee}}htp0to COONOa(O N00h(OtOMN
t
4'1 a, LL9 LLYa
t0 t00 M to h CO co h(
C
co(p ?(p tD
0h
UOM
S
Q
n
r V
(D
W
O
n I- I?I?
s
0
N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
V V
OM r W CO O r tON M O O h O O hN M h f- h r M100 to V NrO COh 0 0
OO
rr
NtO O
rO V hOrNNrr000 CpMrOO lO?et V) MNNNNrrr x0000
C 2 O N(V N M C4 MMMM(V NN(V CV r
(O h C
O to r r N N N N N N N N N N N N N NN N N N N N N N N N N N N N N N N N N N N N N N
,
(ID
0 N CO 0 Cl 0
t
O t-
N
O t` U e' (V x 0 0 0 0 0
N
0
M
V
0
CO (
0 M
00? V v
) M N N N N_
c f
.
LO 0 0 0 r 0
rrr rr
`?
L rr
Oh000 NN NN1000 CO CM N N N NN
r
N N N N N N N N N N N N
r r N N N N N N N N N N N N N N N N N N N N N. N N N N N
v
to
m
OOOOr 0 O0h000(O oW) 0h0 MOhCM h(O W W OMO 0
O
??: M O OD h cp U01O an 10
OOO O t` a? sf O N O M Cl! 07 O NN xO tn(p O O h tT 0 OO M 0(
O
A 0000-hr OCO O N(V r M U(j 0 tp OD C) 0) M M O 00(0 M 0OD h(O U,) 0C14 x00 CO h(0
f M O M N N NN
M
M
V'
i
?. V eM
CO h000r rr O 00000 h(p O O O 7 V V
V cM
N
r r r r .- r r r ?-
m
0000h M0000 (OOOMO(prrMOOhMtO CO V tb 0(phNrOCOOOhr (pMr
?= O O O O OO OR Ooh r(p UO O(p h h N(p M CO r W r t? h O M t? N 07 x0 O N O CO (O ? M N7
3 0000th V M w"MO (n OOOOOOfOresih (U Mlc/ std MOM ---- -r r r rr
N V UOhhOO Mf-00 tO VNrr
m C7
N
0000 CCOO 00
X00 N N 0 O 0000
00 h N to N t-N OOD V ?CO(p N O 000((D tOM N?
MN r-
3 0
V
m
OOOOrNNN M co m co M M N... N0r0h(p t0 t07 V MM CO (V(V C-i C-4 rrr
O? N N N N N N N N N N N N N N r r
(7
O r OR Mr hON(I V Ou) V V M N 00 h(pIt M(O(M M N N N N N NN 777
Orr (V M M77 if V d r wt nCM M N1 cM M M CM CM O M cM M M cM M M tM M M(M cM M M
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
fA 0 0 0 0
N N N N N N N N N (V N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
?.U
a?
007 N Cl r O tO d' O CM O h h 00 tO 00001- V 000 co V h0r rMr O(OV r N tOh V
m
to M0 OtO N_O0h V O O M h to m O w o 7(p 0 h r V CM h N O(p 700(D O(0 O O M
toO co
001.00 LO 0h V O Oh wOh0 Oh(Ot0 t0(Ot- O N(00M(O
o
w
M ??pp
s
s?
t?00(O?NO?NNN700000h ?tMt{{ M N N? htO M N r 0000000000
03-' rr NN(M CMMM V V V V 7 V It M M?MMMMMMMMMMM('?MC00 M M CM M MMMM
r(MN UO 7r tO(0 OR (R hr 00 h 0 M 00(p V V 0h0 CO h NhMO(07--0hO(M N00 xOh
. . .
V ?MMNNNNOO V M?000D h(O anO V 7MMMNNNrrrrrr000
MN
O? Cl)
V
C tl
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
OON NNNN(00M7MM Od' 7? ?tOO tAU ??(Op (NO (OOcotO-ti ti??00O aNO x70000000 N ONi ?N
H
X
C
O
U
conc riser antiflotation.xls
SAND FILTER
FCC-01000
T.
Input Data =_>
Manhole Riser/Barrel Anti-Flotation Calculation Sheet
Inside diameter of manhole = 5.0 feet
Wall thickness of manhole = 6.0 inches
Base thickness of manhole = 8.0 inches
Base diameter of manhole = 6.0 feet
Inside height of Manhole = 7.0 feet
Concrete unit weight= 142.0 PCF
OD of barrel exiting manhole = 26.5 inches
Size of drain pipe (if present) = 6.0 inches
Trash Rack water displacement = 64.1 CF
Concrete Present --_>
Total amount of concrete:
Base of Manhole = 18.850 CF
Manhole Walls = 60.476 CF
Adjust for openings:
Opening for barrel =
Opening for drain pipe =
1.915 CF
0.098 CF
J.E. SCHRUM, E.I.
1 /25/02
Note: NC Products lists unit wt. of
manhole concrete at 142 PCF.
Total Concrete present, adjusted for openings = 77.312 CF
Weight of concrete present = 10978 Ibs
Amount of water displaced =-->
Displacement by concrete = 77.312 CF
Displacement by open air in riser = 137.445 CF
Displacement by trash rack = 64.140 CF
Total water displaced by riser/barrel structure = 278.897 CF
Weight of water displaced = 17403 /bs
Page 1
conc riser antiflotation.xls J.E. SCHRUM, E.I.
I SAND FILTER 1/25/02
FCC-01000
Calculate amount of concrete to be added to riser =_>
Safety factor to use = 1.15 (recommend 1.15 or higher)
Must add = 9035 Ibs concrete for buoyancy
Concrete unit weight for use = 142 PCF (note above observation for NCP concrete)
Buoyant weight of this concrete = 79.60 PCF
Buoyant, with safety factor applied = 69.22 PCF
Therefore, must add = 130.536 CF of concrete
Standard based described above = 18.850 CF of concrete
Therefore, base design must have = 149.385 CF of concrete
Calculate size of base for riser assembly ==>
Diameter = 8.000 feet
Thickness = 36.0 inches
Concrete Present = 150.797 CF OK
Check validity of base as designed =_>
Total Water Displaced = 410.844 CF
Total Concrete Present = 209.259 CF
Total Water Displaced = 25637 Ibs
Total Concrete Present = 29715 Ibs
Actual safety factor = 1.16 OK
Results of design =_>
Base diameter= 8.00 feet
Base Thickness = 36.00 inches
CY of concrete total in base 5.53 CY
Concrete unit weight in added base >= 142 PCF
Page 2
200?.
THE JOHN R. WADAMS COMPANY, INC.
LETTER OF TRANSMITTAL
To: Todd St. John
Date: March 1, 2002
Division of Water Quality
Environmental Sciences Branch
4401 Reedy Creek Rd.
Raleigh, North Carolina 27607
Re: The Gardens at Wakefield Job No.
Sand Filter Design Calculations
I am sending you the following item(s):
** FEDERAL EXPRESS **
FCC-01000
COPIES DATE NO. DESCRIPTION
3 3 Sand Filter Design Calculations
3 3 Sand Filter and Site Plans and Details
These are transmitted as checked below:
? As requested
® For approval
? For review and comment
Remarks:
? For your use
Copy to: Mike Munn, P.E. Signed:
FOR INTERNAL USE ONLY
® Copy Letter of Transmittal Only to File
? Copy Entire Document to File
CIVIL ENGINEERING • LAND PLANNING • SURVEYING
PO Box 14005 • Research Triangle Park, NC 27709 • (919) 361-5000 • fax (919) 361-2269
www.johnrrncadams.com
QUALPOND.XLS
Sand Filter
FCC-01000
Water Qualitv Pond Desian Sheet
Project Name: THE GARDENS AT WAKEFIELD
Designer: J. E. Schrum, E.I.
Job Number: FCC-01000
Date: 1/25/02
Ks = 3244.8
b = 1.3769
Calculation of Runoff Volume required for storage
The runoff to the pond for the 1" storm detention requirement is calculated using the SCS curve
number method. Impervious areas that directly enter the pond are counted as Directly Connected
Impervious Areas (DCIAs). No infiltration calculation will be provided for these areas. Areas
not directly connected will be accounted for in a composite curve number.
From SCS Soils Survey map, predominant hydrologic soil type = B
Using basic SCS runoff methodology, with no ac
to initial abstractions (0.2*S and 0.8*S).
Impervious Area, directly connected (DCIA) _
@CN=
Other areas draining to pond (not DCIA) _
@CN=
Runoff from DCIAs =_>
Ijustments made
2.15 acres
98
2.09 acres
61
Precipitation amount = 1.0 inches
S = 0.204 inches (calculated)
Q* = 0.791 inches (calculated)
Runoff volume = 6173 CF
Runoff from non-connected areas =_>
Precipitation amount = 1.0 inches
S = 6.393 inches (calculated)
Q* = 0.000 inches (calculated)
Runoff volume = 0 CF
Therefore, total runoff from precipitation in question = 6173 CF
This amount of runoff must be stored in the pond above normal pool elevation,
and be released in a period of two (2) to five (5) days, by an inverted PVC
siphon, the invert end of which is set at permanent pool elevation.
J.E. SCHRUM, E.I.
Page 1
STAGE-STORAGE.XLS
SAND FILTER
FCC-01000
Stage-Storage Function
a„
Average Incremental Accumulated Estimated
Contour Contour Contour Contour Stage
Contour Stage Area Area Volume Volume w/ S-S Fxn
(feet) . (feet) (SF) (SF) (CF) (CF) (feet)
288.0 0.0 3500
290.0 2.0 5080 4290 8580 8580 2.03
292.0 4.0 7323 6202 12403 20983 3.88
294.0 6.0 9742 8533 17065 38048 5.98
295.0 7.0 11028 10385 10385 48433 7.13
Storage vs. Stage
60000
50000
40000 y = 3244.8X''3759
R2 = 0.9985
30000
m
0
N 20000
10000-
0
L0.0 2.0 4.0 6.0 8.0
Stage (feet)
KS = 3244.8
b = 1.3759
J.E. SCHRUM, E.I.
1/25/02
1 OF I
QUALPOND.XLS
Sand Filter
FCC-01000
Calculation of depth required for runoff storage pool (above normal pool)
Normal pool depth (above invert) = 0.00 feet
Storage provided at permanent pool depth = 0 CF (calculated)
Total storage required for normal + storage pool = 6173 CF
Stage (above invert) associated with this storage = 1.60 feet
1 Therefore, depth required above normal pool for storm storage = 1.60 feet
19.15 inches
J.E. SCHRUM, E.I.
Therefore set crest of principal spillway at stage = 5.00 feet (Note: crest elevation is set based upon the
and EL = 293.00 feet detention aspect of the sand filter.)
At principal spillway crest, storm pool storage provided = 29710 CF
Page 2
sand filter drawdown.xis
Sand Filter
FCC-01000
«.> Sand Filter Drain Pipe Design Sheet
I
' D siphon = 6 inches
No. siphons =
II 1
.
Ks = 3244.8
b= 1.3759
_
Cd siphon = 0.60
Siphon Invert = 286.50 feet
Volume @ Normal Pool = 0 CF.
Basin Invert = 288.00 feet
WSEL
(feet) Vol. Remaining
c Siphon Flow
cfs Avg. Flow
cfs Incr. Vol.
c Incr. Time
sec
289.900 7847 1.675
289.746 6984 1.634 1.655 863.8 522.1
289.591 6148 1.591 1.612 835.5 518.2
289.437 5343 1.547 1.569 805.6 513.4
289.282 4569 1.502 1.525 773.6 507.4
289.128 3830 1.456 1.479 739.3 499.9
288.974 3127 1.408 1.432 702.1 490.5
288.819 2466 1.358 1.383 661.4 478.3
288.665 1850 1.306 1.332 615.9 462.4
288.510 1286 1.252 1.279 564.1 440.9
288.356 783 1.196 1.224 502.7 410.6
Drawdown Time = 0.06 days
By comparison, if calculated by the average head over the orifice (assuming
average head is half the total depth), the result would be:
Average driving head on orifice = 1.450 feet
Orifice composite loss coefficient = 0.600
X-Sectional area of 1 - 6" inverted siphon = 0.196 ft2
Q = 1.1384 cfs
Drawdown Time = Volume / Flowrate / 86400 (sec/day)
Drawdown Time = 0.08 days
Conclusion : Use 1 - 6" Diameter PVC drain pipe to drawdown the accumulated
volume from the 1.0 " storm runoff, with a required time of about 0.07 days
Therefore, the pipe will not constrain the drainage of the sand media.
J.E. SCHRUM, E.I.
1/25/02
SIPHONS.XLS
sand filter drawdown.xls
Sand Filter
FCC-01000
Drainage through the Sand Media:
J.E. SCHRUM, E.I.
1/25/02
Per NC DENR DWQ, the sand to be used in the filter is to be less than 2 mm in average diameter.
DWQ assumes this sand to have a permeability of 0.04 gal/min/SF (with 1 foot of head over the sand surface).
Average depth of water over sand surface (1/2 maximum depth) = 0.95 feet
The DWQ assumption for sand permeability will be used.
Calculation of drawdown time through the sand =>
Surface area of horizontal sand surface = 1758 SF
Assumed permeability of sand = 0.04 gal/min/SF
Volume stored during storm of interest = 7847 CF
Time required to drawdown through the sand media = 0.58 days
In this case, the sand media is the restricting factor, resulting in a drawdown time
of 0.58 days (13.9 hours). This is within the DW4 requirement that requires the sand filter
drained within a 24 hour time period.
SIPHONS.XLS
i
II
CA
o
c ?
n
O. N
E (L)
0 Z
N 'L
E to
a
? '0 N
' LO C
04 (D
lL O
M ~
c X t
02
m N
. m
N
3 0
o
0 $
CL I °
m . W
I ?
13
C
C
!6
f
o E
o E
_ o
A ?
J _ v
m
T o
y N
O
0 0 0 0 0 0 0°
C W C
Cl) °N N -
($40) Mow
m N _
c m e m 0 m
°ooo o o°o Co °a o o°o-oo
.-06M0O(o(V O(M
O N r N 0 0 N
II
zw
o O O
'000
?- 11 11
m II v
?JNU
Z 11 t N
0 1`p v C II W
W m > J
W p m 11 11 11 If 11
LL z
Y p?ZOUN0 0 00 00 00 00
Z.
W
N `N Z CO 0)
W W. mm?a3UU
0o ~ O?COOMtiN O
J
? ON LL N W OO vi r- co co
N to
(? O 0 m w N N m m
3 M 7 7
•6 = U N W Q A C C N m ? c C
0F-IL? ?(n UEE w m UEE
m I- I- O Goco0 o Loo
6 4 ?NNN Cj co ..CMO c c
p1 O N N t?l 11 O
C CL M O W 11 11 O.
O Cf J m Q NO 11 'o
O dj O
O
E .. Q w t 11 N p LL IT
O
RZ :: w ea .4+N?msT ?(0 c tt o m 3 n m?waOH m Of
LM L E
to.o?'a?i ?.lo - ow Av111 to ±au Oo0mmmawi o aIQ•CL
t?aaa SCJF- v fgY flN SN Uz2aaIT a SC'!f o
` OrMtOO?CO
m 00000 r.-
m R
N
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0-4
U
OoooOOo
N 0 0 0 0 0 0 0
,. 0000000
w
oOOOOOa
0 0 0 0 0 0 0
r O O O O O O G
rrO(OMtA
O O O O O M
r to to 0i t1i000
C? rr-r?NNN
m 3U w
F
M C9 W? CO M O Il?
C CA to tJ) 0 0" O -
r
mU?
S
q M UA CCR MAN
00m CA 00?
? c
w Cl 0 0 0 Cl 0 0
O 0 0 0 0 0 0 0
?
m w
a?
` OOOOOOO
CD ooOOO0
m 0000000
3 ?
? w
0 0 0 0 Cl 0 0
0 0 0 0 0 Cl 0
O 0 0 0 0 0 0 0
3
O
OOOrM1A f?
m O CC-0 zol z z
m+ N N N N N N N
N
OOr1?O V M
G? OOOh NCO 1:
NM et°'3cl)O
r •- N
to
OCOM 00(OCn
3 CEO-N't1 0
O ?tlF/
C w
m
E
H
O O
O N
Xdl
CA
C
.j
O
V
.N
CS
N O n n t` LA N M t- LA M r O M M r`(0 W LOV; V M M N N N N r r r r r r r ra-0 0 0 0 0
mN (V (.IN(V (V (V rr r re-.-000iCCOOCCOCCG000000000000000
to
l?6
CL Z
m R
N
O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 OO O O O
V 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 C 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
N 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 C
0 0 0 0 0 0 0 0 0 0 0 0 O.O O O O O O O O O O O O O O O O O O O O O O O O O O O O
` O O O O C 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
3
LArr NMMO(Or r v Nr-MMMO(0 NOa0(OLAMrOMtl- (0W V•MNrrOMM
OL M MLA r h M M V' M f,.-: O M to t*-: M M O M ? M M CD 00 OR OR OR OR I, t? f: i, ?? h h h r,.: F: q
4 a+?r N MC! A V wow 0r-t-nf- r• t` w r*r.r.t.r?r?r?r?r?hhht?hl?hl?hi?hl?l?h
?CL+ O N N N N N N N N N N N N N N N N N (V N N N N N N N N N N N N N N N N N N N N N N N
m U ,
F
N Mr- IT M M LA m0 M LA LO O O(O MO O W LAN O W LA Mr M W 0 W M Nr MOO fl- (O LA M?
OLAMNrMt`MNMMOON(OM7M V V' V clgq MNNNNrrrrrrr000000
wNM V' LA LO CO ti CO OO M O) O 00- -r a- rr r r r -- rf- r r r e- rr
m O r r r r r r r r r r r N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
mV
S
?MNMi M LLO Nap MOMONf000w M0V - 0 MMtN00NN. . . . .M?r00000000
0 NM V 0LO W r-W OOM M 0 o 0 r- a --- -r -- a- rrrr
L r r- r c- r r r r r r r- N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
O (Q
F, m
N .
LL "'-OOOOOOOOOOOOOONLAMOOI?LA Me? N ??{{OrCO(OMh OOMN??}}OMr (Doll
(n vw0000000000000O.r- NCOrM Ot0Na0LON0)fl- W V: M M (MM V; V;(Olh
0 OGO000000C0000 LO W O O O 0 r'. (oV'CO r 00) ti CO LA A MN r O M 00 1,- to q) LA
M V' LA LA LA V' V• V' d• V' V• M M M M M M M M N N N N N N
L
m
N_
0 0 0 0 0 0 0 0 0 O.O O O O t? N (O M r aD O V' N V' 0 0 e? ? ? 0 00 00 0 V' M (O M N N M
0 0 0 0 0 0 0 0 0 0 0 0 0 0 CO M V' I? V' W M t? N 1? M MLA N M V' r M 00 (0 V' M N r O M
300000000000ooo(q u5 1-r?r-0(ULO0V ;r mm MNNNN - rr -r--- --0
i
m
0 0 0 0 0 0 0 0 O O O O O O ? N 0M r M0vN V'0 0 re? OOOMO V'M COM NNM
00000000000000COM V'I- V:OO(O t?Nhmo) 0) V 0)C0 CO V; CMN rOM
r?-rrrr?--r
000000000000000NLAr-r,? t,? co(ou) Lpv V:vi mmN(V (V (V 0
3
0
O(MI?O V'CO7LAGO7 V'(OOOOrMMMMMMNNNNNNNNrrrrrrrrr
WCACA000CV NN(V('MM('7MMMMOM CO COM M(M CM COM(MMMM('M ('M CMMMMOMM
m 00 00 00 M M M M M M M M M M M M M M O M M M M M M M M M M M M M M M M M M M M M M M
? N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
O
M n CD MNN IT OOM pl? i?r MRMOM LA(o Co LA O N LA M r 001000 LA O N P,.: N LA.. N r C0
mONN(M(7 r V'OMLAMMOC O(?MOO r?r O0 r-V' Lp V'O MOM V'OCM00O0
MO )o O tO M ? NCO COLD M CO O rN f?N00r M(OM ?I- hI-00MrM(00 00
e? MOOMapV'O
(6r ti-tO 000 Nf?rtA r`t` LO Mr(p MIS r MOO t-(0 V'M NrO(0110 C0 r?1?(O tO LO V'() CO (O
OM V' CO CD O M LO M N N N CO N N 0MM04 ----- OO 01'-0 M C U3 M M M 0(00
Y r r r r
LO ONMr(0 LA O0 V' CO M LA r M 0000 M r V' M N ti N OR t} r M LAN O OO(O Ln M N r O M M? CO
. .. . . . . .
NLAhaO000M00t0 V'MNOMCOhI- (OLA1A V V'MMMNNNNrrrrrrr0000
O r r r r N N N .r r r r r r r
w
C
O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O
. . . . . . . V.. . . . . . . . . . . . c? . . . .
'd'(OOOON'Lt(U000N V'COCOON (OV Od'LOtNALApLO A (0 0 (NO 0 (0 (0 0 ntitit- ?OOD00000CCOOODD00) 00)
?rrr N N N N N M Cl) Cl) Cl) It A V'
H
N
X
M
c
O
U
r
_O
LL0)
O
c
m
N
a
Z
U U)
E
a
? lT
O C
O ,C
C X U
0? m m
L 0 m
F-a:W
0
0
o g
O
C ?
0 o
co
•p C
o E
$ o
C f? E
O ?
J ?_ o
O
N
O
0
0 0 0 0 0 0 0
M N N ' O 6 O
NO) -Ij
m m
C w t w w
000000)00(MO
0 0 0 0 0 10 0 0 r O
r 0 m606 06 CV O6
(D Nr NOON
11 it
000
qq
0. O 0
N
? II II
mfl ?3
?..JNU
Z II t m
0 m vs, W
W m J
W o e 11 II 11 II II
Li z q ?av (`om (o `m
Y Ow z U O N C O M M M M
z
W
w co CO)
0 0 Q1 N LL LL M
z 0: m m -4)5 L)
r
K
Ill 11i
R CO J O M V O N N 0
Q?N U.. H N O r M 6LoP N y N
C900 cl
4: .0.. OON rr M .0.. 4:
W U U z U M U>
'O=UN W Q LL._._ d d LL C C
0 E- IL r -? CQ U E E (D w U E E
m „01.0 co Goo 0 vI- o
CNNN tt?-000 0 0 0 •• 'pM sf N
C N
O
O a M N > N ? m 11 11 O.
O N II
O y cm J m Q N 11 11 O$
E .. t m tQ LL FL T c
3 m G OO ?, p O 0 O_ O p
10 Z C pLa 2 02 5CDE La
= O N 6f
c m m p/.. O m C min WCn?I- E O
11 If Offl 11 It
11
•? •? m ' N 'p fl 'am-_. lY0 N N (Y6 0 'p 11 It
L10 m y m= >,. n Q H. 2,11 O Oct (x6 0 0 0 0 0 !. Q tz. F-
t?aaoof- xa (AY ON 5nl 0z?0- n.0- 0-
> xc7i-v
` Or N"C OR N(O r
000 Cr•C r
" - .
1U.
m 19
l00
co
0 0 0 0 0 0 CO 0
0 0 0 0 0 0 0 0
0700000 C?0
w A
O,
V
00000o00
N 0 0 0 0 0 0 0 0
` C O C 0 0 0 0 0
C)
0 0 0 0 0 0 0 0
L
3 O
rr OONin hn
O CO CO CO OO r ? O t0
O O N N N N
m (? O
NCO MC-A
MM(C)CA'NOO
0(A Oi (AO rCV
fn Of rr
x
(C)IOMN OEM M'N
MMCq to V NOO
`? (310>Oi [A O?CV
r r
m
0 0 0 0 0 Cl 0 0
0 0 0 0 0 0 0 0
0 CO 0 0 0 0 0 0
O
m C>!
f1'
` 00000000
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
m
0 0 0 0 0 0 0 0
0 0 0 0 0 0 C. 0
C O 0 0 0 0 0 0 0
O
OOON M (0O N
Cit co Go OC co OD co OCI O
O OOOOOOwww
NNNNNNNN
O O ?t CA M (O CO 00
M
CQ OOU') 't co m0
C*4 (D to
$ r cm V
O It P.: CO NN Cn 00
OOrMtpONln
O r r
C
0 0 0 0 0 0 0
O O CV 4 (O co C> C*NJ
E-
H
N
X
C6
c
U
Q
41 6)rM V V Mr (OtpN0ORgU( CrlNr06)COf*- q q nUn It It CMMMNN...7 777
?' CV NCMMMCMMCOCV CV CV CV ?"?-'t"'ra-%s=rCCO00CO00000000COOC000
't7 V
C
t0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
00000000000000000000000000000000000000000
mooooooociooooo00000000000000ooooocooooccoo
m ..
? R
O?
V
O
LL
M
00000000000o00000000000000000000000000000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
N 0 0 0 0 0 0 0 0 00 0 0 C >O 0 0 0 0 0 0 O CI 0 0 0 0 C>40 0 0 0 00 0 0 0 0 0 0 00
°
°
°O
°
°
°
°
°°°
00°
°
°
°°°
°
°°°
°
°
°
°
°
°
°
°
°°°
°
°
°
°
°
°
°
°
o
oo
o
oo
O
o
0
0
0
0
00
0
00
0
0
00
0
0
0
0
00
000
0
0
0
0
00
0
0
0
`"? ooooo00oooo0ciooocooooo00000000ooooococooo
$J
NrNNr(O nNOM(M(M CM 0 W M MW M co W w M?--M r- to M N 0 0 O0 to V MNNr00
O MO1?et'-h(I O 'It CO r N N N r r O O O O g q()? O CO OO 00 aq CO CO I: f-: fl? hf? t" h; <O
CV V)MAtf)0(0(0 n h CD CO O CO CO M CD CD M CD t- t`r- t`t+t- tit- t- r- nr- t`t`hht-t+t•nt-
N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
V
O O?NNtO NOOr h to O CO r ti M O O (N 6)(O M Co CO CO V N O 00 (D M(M Nr 06) CO n CO(()
-
006)0 CO(Od:rhN tn(O(O(O(O to U( ? q1t It q M M M N N N NNrrr?r?e
00000
C ------- N N
N
N N N
N N N N
N N
yj
U ? N
N N N
N N N N N N N N
N N N N N N N N
N N
v
O O)hN Nth N O Or ? M 00 hM6)tO N 6)(O M O CO CO It N O 00 (0 LO Cr) NrO O CO h(O to
Oa! qO OR (P cj r t'N Uq C0 (O CO CO (n Un?? q1t q v! M q N N N N Nrr e-rrr00000
L ems' Mr N N N N N N N N N N N N N. N N N N N N N N N N N N N N N N N N N N
?
m
C) C, M M
W
N r- 10
N
?
OOOOOO
rn
9
0
V
°
N
N
°
0
0
r
w tUn Iq
t
O
u
n
a7 CO t6 U
tn(O
6)
O
OOt
A N
i
ceO
C
OO V
r- V
rn
C OOOOOOOOO(TCO(MMN0WW t[) M to CACD(O et MN00W0tnV MN C MW t- W
M16 W0 O(O to LO to st V'st <t st CO ctMMMMMMMM N N N NN
?
?
m
` O O O O O O O O O CO f- O N O CO I- CO LO V CO O) CO MM CO t• O t- t` 0) NN(M IAN OO CO V V
OOOOOOOOOer t
rNN6)
(OtAMNrq
CO ID
?
V UD MCO M 6)(O N 6)(O NO C
y ?
?
h
R
ti
000000000CMr tri tO '4- (V ?OtAOf- t- t0 t(i W) sr sr MCMMN(V NNNrrrrrrr
r r r r r r
m
Mo
?
eV{
O
OOOMCMOM
((
OOOOOOOOO V II?NNMtti(OO(OO? 0)?
~
C%
M
NOCM
(OtN0(O)N?0
O 6
)
I
(
O
D
O ?t
9t
000000000 r)
0Lo vci
O 6)o r`I-? (O ui to V V 6 MMNNNC"i c,4 e-r z
-
-
r r r r
O
1170 VCOMhrtfl (AN V tp t(7 V V V V MMMMMNNNNNNN N r r r r r r r r r rr
. . . . . . . . . . . .
. . . . . .
.
. .
.
m .
. . .
. .
. . .
O O O O r r N N N M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M
Q! N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
?
MO V O(O(OM0000)rMhng gcq 0MO V t?rOt`t-MOCMONCOtOgCO V R70CD V
m
O) 0(n tAMOCO CA fMOMOO)1!'/ (V CA C?h O(O fM?OCO V <TNNa000)N.- V CV 00?
i?tC)
?
M ?
rCOhMt?CD CO t? tp tArNN6)CO COON(Orf?Mr0a1 <TO N(OOrO
COs OO
tArh(p (6h0000r0f0 (O NOI?IA VN06)I?(O tAMNr000CptinO(A V V'MM
(n C00(0) (0 0)
O
M
Cl)CM
--
N
0000
NNNMN C
M MM
NN C
M MMMMMMM
M MMMC
MMMCM
N
6) (O CO M O CO O r O CO O N P,: CM r O O r q O Q) M CO M O U7 r CD (n M r g n O M N r 0 0 CD h
. . . . . . . .
3
C N N N N N N N N- O O M N r O 0 co 0 O 1n . V V M M M N N N N r r r r r r r 0 0 0
r r r r r r
C t)
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
(O CO ON V CO 000 CV It Co D 0 N CO CDO(V t(OCOONcc}?Co000fV d'tOCOONd'COCOOCV ?'(O
rr NNNNNCMMMMCM V V V V Looi7wow(O CO COCOt-tl- ? CO CO O O CO O)6) 06)
e
E
H
N
X
(7)
C
3
O
U
a'
}
O
O
LL
U
0
T ?
C A
Q N
U Z
N ?
E
a
N
O al
O C
O
C X L
L O 2
-0m
4)0
m
Paa
L ++ L
C ql C w w w
0000000000m0000?°0
?O ri M OO O co CV ol,:
O a)- NOON
Z II 'G 'm
? ? m C 11 w
I 9 Wm ?J=
w om „11 II II 11 .
Z ?3:Z3.0 m?ac`o
Y ptYZOUNOUmo000m
Z
H H
m m CO LL
w W m m m m U U
DfO J 00 VO_'ONO n
QoN U. N to 0008) OMa N
.m.
O O O > > N VN
LLIUNUZ P
13 m LL C C m m
01-LL (n a E E w w
co to o co co Cl 0
'O CM N(V d'M 00 CG
='-T N P,4 N 00 ••00 N II
C C. .. j N 11 11 11
7
O N ` Q. m It 3 0 m
E .. 01 t Q tt m LL
O
NZ •? r0? m W In
c ? o m c mv?win01° 'E
4) 4)
O "O' w m it 11 11 m 11 11 a+ 11 X N YN lY6 N 7
•? O
a.aDDP =t11°? ?Y o ER c°?z2aaa.o-
m m
R42
000
N
_L 11 11
rou ci3
?JNU
00000000
N 0 0 0 0 0 0 0 0
?L 0 0 0 0 (D 0 0 0
T
0 0 0 0 0 0 Cl 0
0 0 0 0 0 0 0 0
0 0 0 0 00 40 0
o ??ontic`?vCO
0
o OD 00 0)0) o c%i v.v
mU v
was
O U') O tl t.- Co M O
?O CO COON`- " IA 00
U i r
OORR
w w00)ONco
m
w 0 Co 0 0 0 0 0 0
0c'
O 0 0 0 0 0 0 0 40
m t1
_M
00000000
L o0000o00
3 00000000
m
0 0 0 0 0 0 0 Co
Co 0 0 0 0 0 0 0
O 0 0 0 0 0 0 0 co
0
Off. NNNNNNNN
a?
0 Co 0 0 v v 0 N
W 00000))toN ??
M V'M000)OD
O a-N It l-
OMONN 000)
3 00(h t?N? ?NN
C
0 0 0 0 0 0 0 0
? OCV sr <G 00C??
?E
E"
y
X
O!
C
O
U
M)
N
Q
D:
}
O
O
LL
°
°
°
°
°
°
°
°
°
°
°
°
°
°
°O
°o°
°
°O
°
°
°
°
°
°
°
°
°
°
°
°
°°°
°
°
°°
°
°
°
o
o
o
o
o
o
o o
o
o
o
o
o
a
o
OO
o
o
O
o
o
o
o
o
o
o
o
o
o
o
oo
o
o
oo
o
o
o
N 0 0 0 0 0 0 0 0 0 0 0 O 0 0 0 0 0 0 0 0 0 0 0 0 C O C C O C G 6 C O O C O 6 0 0 C
t7
00
O O O O O O O O O O O O O O O O O O O
O O
O O O
O O
O O
O O O O O O
O
O O O
O
0 0 0 O O O 0 O O O O 0 0 0 0 0 0 0 0 0 0 O G c; C C O C 6 0 0 0 C C 0 Otj O O C C
3 O
O NUONOhON(O0 V-"MMIDr-0 s}?ee}}htp0to COONOa(O N00h(OtOMN
t
4'1 a, LL9 LLYa
t0 t00 M to h CO co h(
C
co(p ?(p tD
0h
UOM
S
Q
n
r V
(D
W
O
n I- I?I?
s
0
N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
V V
OM r W CO O r tON M O O h O O hN M h f- h r M100 to V NrO COh 0 0
OO
rr
NtO O
rO V hOrNNrr000 CpMrOO lO?et V) MNNNNrrr x0000
C 2 O N(V N M C4 MMMM(V NN(V CV r
(O h C
O to r r N N N N N N N N N N N N N NN N N N N N N N N N N N N N N N N N N N N N N N
,
(ID
0 N CO 0 Cl 0
t
O t-
N
O t` U e' (V x 0 0 0 0 0
N
0
M
V
0
CO (
0 M
00? V v
) M N N N N_
c f
.
LO 0 0 0 r 0
rrr rr
`?
L rr
Oh000 NN NN1000 CO CM N N N NN
r
N N N N N N N N N N N N
r r N N N N N N N N N N N N N N N N N N N N N. N N N N N
v
to
m
OOOOr 0 O0h000(O oW) 0h0 MOhCM h(O W W OMO 0
O
??: M O OD h cp U01O an 10
OOO O t` a? sf O N O M Cl! 07 O NN xO tn(p O O h tT 0 OO M 0(
O
A 0000-hr OCO O N(V r M U(j 0 tp OD C) 0) M M O 00(0 M 0OD h(O U,) 0C14 x00 CO h(0
f M O M N N NN
M
M
V'
i
?. V eM
CO h000r rr O 00000 h(p O O O 7 V V
V cM
N
r r r r .- r r r ?-
m
0000h M0000 (OOOMO(prrMOOhMtO CO V tb 0(phNrOCOOOhr (pMr
?= O O O O OO OR Ooh r(p UO O(p h h N(p M CO r W r t? h O M t? N 07 x0 O N O CO (O ? M N7
3 0000th V M w"MO (n OOOOOOfOresih (U Mlc/ std MOM ---- -r r r rr
N V UOhhOO Mf-00 tO VNrr
m C7
N
0000 CCOO 00
X00 N N 0 O 0000
00 h N to N t-N OOD V ?CO(p N O 000((D tOM N?
MN r-
3 0
V
m
OOOOrNNN M co m co M M N... N0r0h(p t0 t07 V MM CO (V(V C-i C-4 rrr
O? N N N N N N N N N N N N N N r r
(7
O r OR Mr hON(I V Ou) V V M N 00 h(pIt M(O(M M N N N N N NN 777
Orr (V M M77 if V d r wt nCM M N1 cM M M CM CM O M cM M M cM M M tM M M(M cM M M
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
fA 0 0 0 0
N N N N N N N N N (V N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N
?.U
a?
007 N Cl r O tO d' O CM O h h 00 tO 00001- V 000 co V h0r rMr O(OV r N tOh V
m
to M0 OtO N_O0h V O O M h to m O w o 7(p 0 h r V CM h N O(p 700(D O(0 O O M
toO co
001.00 LO 0h V O Oh wOh0 Oh(Ot0 t0(Ot- O N(00M(O
o
w
M ??pp
s
s?
t?00(O?NO?NNN700000h ?tMt{{ M N N? htO M N r 0000000000
03-' rr NN(M CMMM V V V V 7 V It M M?MMMMMMMMMMM('?MC00 M M CM M MMMM
r(MN UO 7r tO(0 OR (R hr 00 h 0 M 00(p V V 0h0 CO h NhMO(07--0hO(M N00 xOh
. . .
V ?MMNNNNOO V M?000D h(O anO V 7MMMNNNrrrrrr000
MN
O? Cl)
V
C tl
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
OON NNNN(00M7MM Od' 7? ?tOO tAU ??(Op (NO (OOcotO-ti ti??00O aNO x70000000 N ONi ?N
H
X
C
O
U
conc riser antiflotation.xls
SAND FILTER
FCC-01000
T.
Input Data =_>
Manhole Riser/Barrel Anti-Flotation Calculation Sheet
Inside diameter of manhole = 5.0 feet
Wall thickness of manhole = 6.0 inches
Base thickness of manhole = 8.0 inches
Base diameter of manhole = 6.0 feet
Inside height of Manhole = 7.0 feet
Concrete unit weight= 142.0 PCF
OD of barrel exiting manhole = 26.5 inches
Size of drain pipe (if present) = 6.0 inches
Trash Rack water displacement = 64.1 CF
Concrete Present --_>
Total amount of concrete:
Base of Manhole = 18.850 CF
Manhole Walls = 60.476 CF
Adjust for openings:
Opening for barrel =
Opening for drain pipe =
1.915 CF
0.098 CF
J.E. SCHRUM, E.I.
1 /25/02
Note: NC Products lists unit wt. of
manhole concrete at 142 PCF.
Total Concrete present, adjusted for openings = 77.312 CF
Weight of concrete present = 10978 Ibs
Amount of water displaced =-->
Displacement by concrete = 77.312 CF
Displacement by open air in riser = 137.445 CF
Displacement by trash rack = 64.140 CF
Total water displaced by riser/barrel structure = 278.897 CF
Weight of water displaced = 17403 /bs
Page 1
conc riser antiflotation.xls J.E. SCHRUM, E.I.
I SAND FILTER 1/25/02
FCC-01000
Calculate amount of concrete to be added to riser =_>
Safety factor to use = 1.15 (recommend 1.15 or higher)
Must add = 9035 Ibs concrete for buoyancy
Concrete unit weight for use = 142 PCF (note above observation for NCP concrete)
Buoyant weight of this concrete = 79.60 PCF
Buoyant, with safety factor applied = 69.22 PCF
Therefore, must add = 130.536 CF of concrete
Standard based described above = 18.850 CF of concrete
Therefore, base design must have = 149.385 CF of concrete
Calculate size of base for riser assembly ==>
Diameter = 8.000 feet
Thickness = 36.0 inches
Concrete Present = 150.797 CF OK
Check validity of base as designed =_>
Total Water Displaced = 410.844 CF
Total Concrete Present = 209.259 CF
Total Water Displaced = 25637 Ibs
Total Concrete Present = 29715 Ibs
Actual safety factor = 1.16 OK
Results of design =_>
Base diameter= 8.00 feet
Base Thickness = 36.00 inches
CY of concrete total in base 5.53 CY
Concrete unit weight in added base >= 142 PCF
Page 2
THE JOHN R. McADAMS COMPANY, IN
KERR DRUGS REGIONAL OFFICES
SAND FILTER DESIGN CALCULATIONS
WAKE COUNTY, NC
KER 01020
DWQ Project # 970694
J.E. SCHRUM, E.I.
Nove, 21, 2001
24601 1
-1!/H111111,11"
CIVIL ENGINEERING • LAND PLANNING • SURVEYING
PO Box 14005 • Research Triangle Park, NC 27709 • (919) 361-5000 • fax (919) 361-2269
www.johnrmcadams.com
KERR DRUG CORPORATE OFFICES
Sanci f,i°Itel- Desigi7Calculations
General D4,sc.:rp-dam
-Located on the corner of New Palls of the Neuse Road and Common Oaks Drive, Kerr
Drug Corporate Offices will consist of office buildings and associated utilities and
parking. This property is located in the Wakefield Development and is therefore subject
to a 401 Water Quality Certification under DWQ Project # 970694. This permit requires
an approved stormwater management program which meets 85% TSS removal. The
property is also subject to the City of Raleigh Neuse River Basin Stormwater Rules,
which require that all property proposed for development shall submit a nitrogen loading
analysis and determine the impact of stormwater runoff on downstream areas in the two-
year storm event.
The site is composed of one sub-basin. All impervious portions of the sub-basin will be
diverted to a sand-filter in post-development in order to reduce post-development
nitrogen loading and as the means of meeting the 85% TSS removal requirement. The
sand filter will also detain runoff from the two-year storm event to pre-development
levels.
The included Summary of Results demonstrates that the sand filter meets all design
requirements put forth by the NCDENR Stormwater Best Management Practices (BMP,
April 1999). This includes meeting the requirements of surface area in both the sediment
and sand chamber and the volumetric requirements based upon storage of the 1" rainfall.
The sand filter also passes the flow resulting from the 100-year storm event with 0.52 ft
of freeboard from the water surface elevation to the top of berm.
This analysis satisfies the requirements set forth by the City of Raleigh Program for
Nitrogen Control with no further analysis required.
Calculation jllethodology for Stormwater Impact Arrczlysis
• HEC-IIMS version 2.1.2 was used to calculate all flow rates in the report"
Additionally, FIEC-I-IMS was used to route the detention provided by the sand
filter and determine the water surface elevation (WSE) in the pond resulttnS from
each storm event.
• PondPack v7.0 was used to generate the rating curve modeling the outlet
hydraulics of the sand filter. This rating curve was then entered into the reservoir
element in HEC-HMS and utilized to route the sand filter.
• Rainfall data used in the analysis is from USWB TP-40 and NOAA Hydro-35.
• Using the Wake County Soil Survey, the majority of on-site soils were
determined to be Hydrologic Soil Group `B'. Therefore, the SCS Curve Numbers
were selected appropriately.
• On-site topography is from field survey.
• Time of Concentration (TJ was calculated using the Penn State Urban Hydrology
Model software (1989), which calculates the T,; using SCS TR55 method (1986).
• Nitrogen removal calculations were accomplished using the "Neuse River Basin:
Model Stormwater Program for Nitrogen Control", NCDENR - Division of
Water Quality. August 30, 1999.
SAND FILTER SUMRESULTS.xls SAND FILTER
K`R 01020
SUMMARY OF RESULTS
V
V
h
\S
J
-S
SAND FILTER WATER-QUALITY ASPECT*
Aspect Va ie
Sediment Chamber-
SA Required 1570
SA Provided. 2090 ,- . 7--
Vol Required 2354 ,t3
Vol Provided 5456 ,ft3
Sand Chamber -
SA Required 1570 ft'
SA Provided 1593 ft2
Vol Required 2354 ft3
Vol Provided 4422 ft3
I " Storm R/O Vol Re 'd 6374 ft3
I " Storm R/O Vol Prov'd 17018 ft3
Drawdown Time 16.30 hours
TSS Removal Efficiency 85%
DETENTION PERFORMANCE:
J. E. SCHRUM, E.I.
11/14/01
6 av
Pre- , Post-
development development % Change
cfs cfs
2-YEAR STORM EVENT 0.92 0.64 y0% 1
ROUTING PERFORMANCE:
Aspect Value In Value Out
Q, 10.1 cfs 0.2 cFs-
Q10 20.2 cfs 10.4 cfs
Quo 32.5 cfs 28.3 cfs
WSEL, 217.01 ft
WSELio 217.36 ft
WSELioo 217.78 ft
Top of Berm 218.30 ft
HEC-HMS Project: KER 99030 Basin Model.
fii PRE-DEVELOPMENT
HEC-HMS INPUTS.xls
PRE-DEVELOPMENT
KER 01020
HEC-HMS INPUTS
PRE-DEI'ELOPMEi.
Drainage Area Description =_>
Total Drainage Area =
Impervious area = 0.00 AC @ c=
Open / Grassy / Landscaped Area = 0.00 AC @ c=
Wooded Area = 6.41 AC @ c=
Other undescribed area = 0.00 AC @ c=
J.E. SCHRUM, E.I.
11 /14/01
0.95 and CN = 98.0
0.27 and CN = 61.0
0. IS and CN = 55.0
0.00 and CN = 0.0
Total DA = 6.41 AC @ c= 0.15 and CN = 55.0
1
= 0.0100156 sq. miles
Desigir Storm Deseriptiott / Watershed Sensitivity =>
Time of Concentration = 8.3 minutes
HEC-HMS INPUTS.xls
PRE-DEV Tc
KER 0102-0
Time of Concentration Information:
Segment l: Overland Flow
Length = 50 ft
Height = 2.00 ft
Slope = 0.0100 ft/ ft
Manninss'n' = 0.24 Dense Grasses
P (2-year, 6-hour) = 3.6 inches
Segment 2: Concentrated Flow
Length = 606 ft
Height = 40 ft
Slope = 0.0660 ft/ ft
Unpaved
J.E. SCHRUM, E.I.
11/13/01
Time of Concentration minutes
HMS w Summary of Results
Project KER 99030 Run Name : 2-YR PRE
Start of Run 09Aug01 1200 Basin Model PRE-DEVELOPMENT
End of Run l0Aug01 1200 Met. Model 2-YEAR
Execution Time 19Nov01 1900 Control Specs 1-MINUTE dT
.-Y- -9-Lk- Discharge Time of
Element Volume Drainage
Peak Peak (ac Area
(cfs) ft) (sq mi)
PRE-DEVELOPMENT 0.92329 10 Aug 01 0012 0.12855
0. 010
HEC-HMS INPUTS.xis J.E SCHRUM, E.I.
POST-DEV TO DET 11/14101
KER 01020
HEC-HiV1S (NPLITS
TO DETENTION , iREA
Drainage Area Description ==>
Total Drainage Area =
Impervious area = 2.22 AC @ c= 0.95 and CN = 98.0
Open / Grassy / Landscaped Area = 1.72 AC @ c= 0.27 and CN = 61.0
Wooded Area = 0.42 AC @ c= 0. 15 and CN = 55.0
Other undescribed area = 0.00 AC @ c= 0.00 and CN = 0.0
Total DA = 4.36 AC ((b, c 0.60 and CN = 79
-or- 0.0068125 sq miles
Design Storm Description / Watershed Sensitivity =>
Time of Concentration = 5.0 minutes (Assume minimum Tc)
40 HEC-HMS INPUTS.xls J. E. SCHRUM, E.I.
POST-DEV BYPASS 11/14/01
KER 01020
HEC-HMS IMIS
BYPASS DETENTION AREA
Drai?rage Area Description ==>
Total Drainage Area =
Impervious area = 0.00 AC @ c= 0.95 and CN = 98.0
Open / Grassy / Landscaped Area = 1.19 AC @ c= 0.27 and CN = 61.0
Wooded Area = 0.86 AC @ c= 0.15 and CN = 55.0
Other undescribed area = 0.00 AC @ c= 0.00 and CN = 0.0
Total DA = 2.05 AC P. c= 0.22 and CN = 58
-or- 0.0032031 sq miles
Design Storm Description / Watershed Sensitivity ==>
Time of Concentration = 5.0 minutes (Assume minimum Tc)
ID
Sand Filter Design.sls J. E. SCI IRU%v I, E. 1.
Sand Filter 1 11/ 14/01
KER 01020
==> Hydrograplr Generation
The total drainage area, SCS CN and time of concentration are input into HEC-HMS
Drainage Area Description ==>
Total Drainage Area =
Impervious area = 2.22 AC @ c= 0.95 and CN = 98.0
Open / Grassy / Area = 1.72 AC a c= 0.27 and CN = 61.0
Wooded Area = 0.42 AC @ c= 0.15 and CN = 55.0
Other undescribed area = 0.00 AC @ c= 0.00 and CN = 0.0
Total DA = 4.36 AC c= 0.60 and CN = 79
-or- 0.0068125 sq. miles
Design Storm Description / Watershed Sensitivity =>
Time of Concentration = 5.0 minutes (Minimum Tc)
Required Parameters for Sand Filter
The sand filter is deigned per the guidelines established by NCDEHNR.
Rf: "Stormwater Bert Management Practices, ACDEHNR (April 1999)
Sediment Chamber Parameters ===
Surface Area = 1569.6 ft'
Volume = 2354.4 W
Sand Filter Chamber Parameters =
Surface Area = 1569.6 ft`
Volume = 2354.4 ft'
I OF I
i
HEC-HMS Project: KER 99030 Basin Model:
TO SAND FILTER
ISAND ILTER
SAM) FILTEl' SFAGE-STORAG. .M.S
'SAND FILTER
KER 01020
St.wye-Storage Function
Project Name: KERR DRUG CORPORATE OFFICES
Designer: J. E. SCI IRUM, E.I.
Job Number: KER 99030
Date: 11/14/01
Average Incremental Accumulated Estimated
Contour Contour Contour Contour Stage
Contour Stage Area Area Volume Volume w/ S-S Fxn
(feet) (feet) (SF) (SF) (CF) (CF) (feet)
214.0 0.0 3589
216.0 2.0 5995 4792 9584 9584 2.00
218.0 4.0 8961 7478 14956 24540 4.00
30000
25000
t% 20000
U
ai 15000
m
o
10000
5000
0
Storage vs. Stage
y = 3743x'.311
R2 = 1
0.0 1.0 2.0 3.0
Stage (feet)
Ks = 37431
b = 1.3564
4.0 5.0
J.F.
SCIJIZUM, li.l.
11/14/01
I OF 1
Type.... Outlet Input Data Page 1.01
Name.... SAND FILTER OUT
File.... C:\HAESTAD\PPKW\KER 99030\SAND FILTER.PPW
REQUESTED POND WS ELEVATIONS:
Min. Elev.= 214.00 ft
Increment = .25 ft
Max. Elev.= 218.00 ft
OUTLET CONNECTIVITY
---> Forward
<--- Reverse
< --- > Forward
Structure
-----------------
Stand Pipe
Culvert-Circular
TW SETUP, DS Channel
Flow
Flow
and
No.
RI
BA
Only (UpStream
Only (DnStream
teverse Both Al
Outfall
---> BA
---> TW
to DnStream)
to UpStream)
lowed
E1, ft E2, ft
--------- --------
217.000 218.000
212.400 218.000
S/N: 921AO1506A8B The John R. McAdams Company
PondPack Ver: 7.0 (325) Compute Time: 16:30:28 Date: 11-13-2001
Type.... Outlet Input Data
Name.... SAND FILTER OUT
File.... C:\HAESTAD\PPKW\KER 99030\SAND FILTER.PPW
OUTLET STRUCTURE INPUT DATA
Page 1.02
Structure ID = RI
Structure Type = Stand Pipe
-----------------
# of Openings -------------
= 1 ------
Invert Elev. = 217.00 ft
Diameter = 5.0000 ft
Orifice Area = 19.6350 sq.ft
Orifice Coeff. _ .600
Weir Length = 15.71 ft
- Weir Coeff. = 3.000
K, Submerged = .000
K. Reverse = 1.000
Kb,Barrel = .000000 (per ft of full flow)
Barrel Length = .00 ft
Mannings n = .0000
S/N: 921AO1506A8B The John R. McAdams Company
PondPack Ver: 7.0 (325) Compute Time: 16:30:28 Date: 11-13-2001
Type.... Outlet Input Data
Name.... SAND FILTER OUT
File.... C:\HAESTAD\PPKW\KER 99030\SAND FILTER.PPW
OUTLET STRO.CTURE IN-PUT DATA
Structure ID = BA
Structure Type = Culvert-Circular
-----------------
No. Barrels -------------
= 1 ------
Barrel Diameter = 2.0000 ft
Upstream Invert = 212.40 ft
Dnstream Invert = 212.00 ft
Horiz. Length = 45.00 ft
Barrel Length = 45.00 ft
Barrel Slope = .00889 ft/ft
OUTLET CONTROL DATA...
Mannings n = .0130
Ke = 1.5000
Kb = .012411
Kr = 1.0000
HW Convergence = .001
INLET CONTROL DATA...
Equation form = 1
Inlet Control K = .0098
Inlet Control M = 2.0000
Inlet Control c = .03980
Inlet Control Y = .6700
T1 ratio (HW/D) = 1.156
T2 ratio (HW/D) = 1.302
Slope Factor = -.500
Page 1.03
(forward entrance loss)
(per ft of full flow)
(reverse entrance loss)
+/- ft
Use unsubmerged inlet control Form 1 equ. below T1 elev.
Use submerged inlet control Form 1 equ. above T2 elev.
In transition zone between unsubmerged and submerged inlet control,
interpolate between flows at T1 & T2...
At T1 Elev = 214.71 ft ---> Flow 15.55 cfs
At T2 Elev = 215.00 ft ---> Flow = 17.77 cfs
Structure ID = TW
Structure Type = TW SETUP, DS Channel
------------------------------------
FREE OUTFALL CONDITIONS SPECIFIED
CONVERGENCE TOLERANCES...
Maximum Iterations= 30
Min. TW tolerance = .01 ft
Max. TW tolerance = .01 ft
Min. HW tolerance = .01 ft
Max. HW tolerance = .01 ft
Min. Q tolerance = .10 cfs
Max. Q tolerance = .10 cfs
S/N: 921AO1506A8B The John R. McAdams Company
PondPack Ver: 7.0 (325) Compute Time: 16:30:28 Date: 11-13-2001
Type .... Composite Rating Curve
Name.... SAND FILTER OUT
File.... C:\HAESTAD\PPKW\KER 99030\SAND FILTER.PPW
***** COMPOSITE OUTFLOW SUMMARY ****
WS Elev," Total Q Notes
---------------- ------ -- Converge ----- -- ------------------
Elev. Q TW Elev Error
ft cfs ft +/-ft Contr ibuting Structures
--------
214:00 -------
.00 ------
Free -- ----- -
Outfall -----
(no --
Q: ------------------
RI BA)
214.25 .00 Free Outfall (no Q: RI BA)
214.50 .00 Free Outfall (no Q: RI BA)
214.75 .00 Free Outfall (no Q: RI,BA)
215.00 .00 Free Outfall (no Q: RI,BA)
215.25 .00 Free Outfall (no Q: RI BA)
215.50 .00 Free Outfall (no Q: RI BA)
215.75 .00 Free Outfall (no Q: RI,BA)
216.00 .00 Free Outfall (no Q: R I BA)
216.25 .00 Free Outfall (no Q: RI BA)
216.50 .00 Free Outfall (no Q: RI BA)
216.75 .00 Free Outfall (no Q: RI BA)
217.00 .00 Free Outfall (no Q: RI BA)
217.25 5.89 Free Outfall RI,-BA
217.50 16.66 Free Outfall RI BA
217.75 28.19 Free Outfall RI BA
218.00 29.07 Free Outfall RI BA
Page 1.06
S/N: 921AO1506A8B The John R. McAdams Company
PondPack Ver: 7.0 (325) Compute Time: 16:30:28 Date: 11-13-2001
Rating Curve.xls
Riser - Barrel
RER.01020
Rating Curve Calculdflon
'Basin outTow based upon output from PondPacl: rating curve
(See,previous.pa
Stage-Storage Funelfon ->
Ks = 3743
b = 1.3564
Zo = 214
Basin
WSEL
(feet) Basin
Outflow
(cfs) Storage
(ft')
(acre-ft)
214.00 0.00 0 0.000
214.25 0.00 571 0.013
214,50 0.00 1462 0.034
214.75 0.00 2534 0.058
215.00 0.00 3743 0.086
21525 0.00 5066 0.116
215.50 0.00 6487 0.149
215.75 0 00 7996 0.184
216.00 0.00 9584 0.220
216.25 0.00 11244 0.258
216.50 0.00 12971 0.298
216.75 0.00 14762 0.339
217.00 0.00 16611 0.381
217.25 5.89 18516 0.425
217.50 16.66 20474 0.470
217.75 28.19 22482 0.516
218.00 29.07 24539 0.563
J 1?. SCHRIA t, F. 1.
I1;I3101
1 OF I
HMS W Summary of Results
Project KER 99030 Run Name : 2-YR POST
Start of Run 09Aug01 1200 Basin Model POST-DEVELOPMENT
End of Run 10Aug01 1200 Met. Model 2-YEAR
Execution Time 14Nov01 1357 Control Specs 1-MINUTE dT
Hydrologic Discharge Time of Volume Drainage
Element Peak Peak (ac Area
(cfs) ft) (sq mi)
TO SAND FILTER 10.089 10 Aug 01 0005 0.47650 0.007
SAND FILTER 0.21498 10 Aug 01 0436 0.084835 0.007
SAND.FILTER BYPASS 0.64440 10 Aug 01 0008 0.056271 0.003
Junction-1 0.64440 10 Aug 01 0008 0.14111 0.010
HMS * Summary of Results for SAND FILTER
Project KER 99030 Run Name 2-YR POST
Start of Run 09Aug01 1200 Basin Model POST-DEVELOPMENT
End of Run 10Agg01 1200 Met. Model 2-YEAR
Execution Time 14Nov01 1357 Control Specs 1-MINUTE dT
Computed Results
Peak Inflow 10 .089 (cfs) Date/Time of Peak Inflow 10 Aug 01 0005
Peak Outflow 0. 21498 (cfs) Date/Time of Peak Outflow 10 Aug 01 0436
Total Inflow 1. 31 (in) Peak Storage 0.39261(ac-ft)
Total Outflow 0. 23 (in) Peak Elevation 217.01(ft)
HMS * Summary of Results
Project KER 99030 Run Name : 10-YEAR POST
Start of Run 09Aug01 1200 Basin Model POST-DEVELOPMENT
End of Run 10Aug01 1200 Met. Model 10-YEAR
Execution Time 14Nov01 1357 Control Specs 1-MINUTE dT
10
Hydrologic Discharge Time of Volume Drainage
Element Peak Peak (ac Area
(cfs) ft) (sq mi)
TO SAND FILTER 20.151
SAND FILTER 10.430
SAND FILTER BYPASS 3.7914
Junction-1 12.821
10 Aug 01 0004 1.1197 0.007
10 Aug 01 0012 0.72736 0.007
10 Aug 01 0005 0.23072 0.003
10 Aug 01. 0011 0.95808 0.010
HMS * Summary of Results for SAND FILTER
Project KER 99030 Run Name 10-YEAR POST
Start of Run 09Aug01 1200 Basin Model POST-DEVELOPMENT
End of Run 10Aug01 1200 Met. Model 10-YEAR
Execution Time 14Nov01 1357 Control Specs 1-MINUTE dT
Computed Results
Peak Inflow 20 .151 (cfs) Date/Time of Peak Inflow : 10 Aug 01 0004
Peak Outflow 10 .430 (cfs) Date/Tine of Peak Outflow 10 Aug 01 0012
Total Inflow 3. 08 (in) Peak Storage 0.45397(ac-ft)
Total outflow 2. 00 (in) Peak Elevation 217.36(ft)
HM'S' * Summary of Results
Project KER 99030 Run Name : 100-YR
Start of Run 09Aug01 1200 Basin Model POST-DEVELOPMENT
End of Run 10Aug01 1200 Met. Model 100-YEAR
Execution Time 14Nov01 1358 Control Specs 1-MINUTE dT
Hydrologic Discharge Time of Volume Drainage
Element Peak Peak (ac Area
(cfs) ft) (sq mi)
TO SAND FILTER 32.465 10 Aug 01 0004 1.9997 0.007
SAND FILTER 28.283 10 Aug 01 0007 1.6064 0.007
SAND FILTER BYPASS 8.6407 10 Aug 01 0005 0.53102 0.003
Junction-1 36 .635 10 Aug 01 0006 2.1375 0.010
HMS * Summary of Results for SAND FILTER
Project KER 99030 Run Name 100-YR
Start of Run 09Aug01 1200 Basin Model POST-DEVELOPMENT
End of Run 10Aug01 1200 Met. Model 100-YEAR
Execution Time 14Nov01 1358 Control Specs 1-MINUTE dT
Computed Results
Peak Inflow 32.465 (cfs) Date/Tine of Peak Inflow 10 Aug 01 0004
Peak Outflow 28.283 (cfs) Date/Tine of Peak Outflow 10 Aug 01 0007
Total Inflow S.S0 (in) Peak Storage 0.53210(ac-ft)
Total Outflow 4.42 (in) Peak Elevation 217.78(ft)
Qualpond.xls
Sand Filter
KER 01020
Water Quality Pond Design Sheet
Project Name: KERR DRUG CORPORATE OFFICES
Designer: J. E. Schrum, E.I.
Job Number: KER 01020
Date: 11/14/01
Ks = 3897.7
b = 1.3416
Calculation of Runoff Volume required for storage
The runoff to the pond for the 1 storm detention requirement is calculated using the SCS curve
number method. Impervious areas that directly enter the pond are counted as Directly Connected
Impervious Areas (DCIAs). No infiltration calculation will be provided for these areas. Areas
not directly connected will be accounted for in a composite curve number.
From SCS Soils Survey map, predominant hydrologic soil type = B
Using basic SCS runoff methodology, with no adjustments made
to initial abstractions (0.2'S and 0.8'S).
Impervious Area, directly connected (DCIA) = 2.22 acres
@CN= 98
Other areas draining to pond (not DCIA) = 2.14 acres
@CN= 61
Runoff from DCIAs =_>
Precipitation amount = 1.0 inches
S = 0.204 inches (calculated)
Q" = 0.791 inches (calculated)
Runoff volume = 6374 CF
Runoff from non-connected areas =_>
Precipitation amount = 1.0 inches
S = 6.393 inches (calculated)
Q' = 0.000 inches (calculated)
Runoff volume = 0 CF
Therefore, total runoff from precipitation in question = 6374 CF
This amount of runoff must be stored in the pond above normal pool elevation,
and be released in a period of two (2) to five (5) days, by an inverted PVC
siphon, the invert end of which is set at permanent pool elevation.
J.E. SCHRUM, E.I.
Page 1
Qualpond.xls
Sand Filter
KER 01020
Calculation of depth required for runoff storage pool (above normal p6M
Normal pool depth (above invert) = 0.00 feet
Storage provided at permanent pool depth = 0 CF (calculated)
Total storage required for normal + storage pool = 6374 CF
Stage (above invert) associated with this storage = 1.44 feet
J.E. SCHRUM, E.I.
Therefore, depth required above normal pool for storm storage = 1.44 feet
17.31 inches
Therefore set crest of principal spillway at stage = 3.00 feet (Note: crest elevation is set based upon the
and EL = 217.00 feet detention aspect of the sand filter.)
At principal spillway crest, storm pool storage provided = 17018 CF
Page 2
sand filter drawdown.xis
Sand Filter #1
KER 01020
Sand Filter Drain Pipe Design Sheet
D siphon =
No. siphons =
Ks =
b=
Cd siphon =
Siphon Invert =
Volume @ Normal Pool =
Basin Invert
=
6 inches
1
3897.7
1.3416
0.60
212.50 feet
0 CF
214.00 feet
WSEL
feet Vol. Remaining
c Siphon Flow
cfs Avg. Flow
cfs Incr. Vol.
c Incr. Time
sec
215.761 8328 1.638
215.617 7424 1.598 1.618 903.3 558.3
215.472 6548 1.557 1.578 876.2 555.3
215.328 5701 1.515 1.536 847.2 551.4
215.183 4885 1.472 1.494 816.3 546.4
215.039 4102 1.428 1.450 782.9 539.8
214.894 3355 1.382 1.405 746.5 531.2
214.750 2649 1.335 1.359 706.2 519.9
214.605 1988 1.286 1.310 661.0 504.5
214.461 1379 1.235 1.260 608.9 483.2
214.317 833 1.181 1.208 546.3 452.2
Drawdown Time = 0.06 days
By comparison, if calculated by the average head over the orifice (assuming
average head is half the total depth), the result would be:
Average driving head on orifice = 1.381 feet
Orifice composite loss coefficient = 0.600
X-Sectional area of 1 - 6" inverted siphon = 0.196 ft2
Q = 1.1108 cfs
Drawdown Time = Volume / Flowrate / 86400 (sec/day)
Drawdown Time = 0.09 days
Conclusion : Use 1 - 6" Diameter PVC drain pipe to drawdown the accumulated
volume from the 1.0 " storm runoff, with a required time of about 0.08 days
Therefore, the pipe will not constrain the drainage of the sand media.
J.E. SCHRUM, E.I.
11/14/01
SIPHONS.XLS
sand filter drawdown.xis
Sand Filter #1
KER 01020
Drainage through the Sand Media:
J.E. SCHRUM, E.I.
11/14/01
Per NC DENR DWQ, the sand to be used in the filter is to be less than 2 mm in average diameter.
DWQ assumes this sand to have a permeability of 0.04 gal/min/SF (with 1 foot of head over the sand surface).
Average depth of water over sand surface (1/2 maximum depth) = 0.8805 feet
The DWQ assumption for sand permeability will be used.
Calculation of drawdown time through the sand =_>
Surface area of horizontal sand surface = 1593 SF
Assumed permeability of sand = 0.04 gal/min/SF
Volume stored during storm of interest = 8328 CF
Time required to drawdown through the sand media = 0.68 days
In this case, the sand media is the restricting factor, resulting in a drawdown time
of 0.68 days (16.3 hours). This is within the DWQ requirement that requires the sand filter
drained within a 24 hour time period.
SIPHONS.XLS
conc riser antiflotation.xis
SAND FILTER
KER 01020
Manhole Riser/Barrel Anti-Flotation Calculation Sheet
Input Data =_>
Inside diameter of manhole = 5.0 feet
Wall thickness of manhole = 6.0 inches
Base thickness of manhole = 8.0 inches
Base diameter of manhole = 6.0 feet
Inside height of Manhole = 4.6 feet
Concrete unit weight = 142.0 PCF
OD of barrel exiting manhole = 30.0 inches
Size of drain pipe (if present) = 1.5 inches
Trash Rack water displacement = 64.1 CF
Concrete Present =_>
Total amount of concrete:
Base of Manhole = 18.850 CF
Manhole Walls = 39.741 CF
Adjust for openings:
Opening for barrel = 2.454 CF
Opening for drain pipe = 0.006 CF
J.E. SCHRUM, E.I.
11/14/01
Note: NC Products lists unit wt. of
manhole concrete at 142 PCF.
Total Concrete present, adjusted for openings = 56.130 CF
Weight of concrete present = 7971 lbs
Amount of water displaced =_>
Displacement by concrete = 56.130 CF
Displacement by open air in riser = 90.321 CF
Displacement by trash rack = 64.140 CF
Total water displaced by riser/barrel structure = 210.591 CF
Weight of water displaced = 13141 lbs
Page 1
conc riser antiflotation.xls J.E. SCHRUM, E.I.
SAND FILTER 11/14/01
KER 01020
Calculate. amount of concrete to be added to riser =_>
Safety factor to use = 1.15 (recommend 1.15 or higher)
Must add = 7142 Ibs concrete foebuoyancl
Concrete unit weight for use = 142 PCF (note above observation for NCP concrete)
Buoyant weight of this concrete = 79.60 PCF
Buoyant, with safety factor applied = 69.22 PCF
Therefore, must add = 103.175 CF of concrete
Standard based described above = 18.850 CF of concrete
Therefore, base design must have = 122.025 CF of concrete
Calculate size of base for riser assembly =_>
Diameter = 8.000 feet
Thickness = 30.0 inches
Concrete Present = 125.664 CF OK
Check validity of base as designed =_>
Total Water Displaced = 317.406 CF
Total Concrete Present = 162.945 CF
Total Water Displaced = 19806 Ibs
Total Concrete Present = 23138 Ibs
Actual safety factor = 1.17 OK
Results of design =_>
Base diameter = 8.00 feet
Base Thickness = 30.00 inches
CY of concrete total in base = 4.52 CY
Concrete unit weight in added base >= 142 PCF
Page 2
VEL DIS.xIs
24" RCP - UNDEFINED CHANNEL
KER 01020
NRCD Land Quality Section
Pipe Design
Entering the following values will provide you with
the expected outlet velocity and depth of flow in a
pipe, assuming the Mannings roughness number is
constant over the entire length of the pipe.
flow Q in cfs : 10.43
slope S in % : 0.89
pipe diameter D in in.: 24
Manning number n : 0.013
Flow depth (ft) = 1.03
Outlet velocity (fps) = 6.863
NRCD Land Quality Section
NYDOT Dissipator Design Results
Pipe diameter (ft) 2.00
Outlet velocity (fps) 6.86
Apron length (ft) 12
AVG DIAM STONE THICKNESS
(inches) CLASS (inches)
-------- ----- ---------
3 A 9
<< 6 B 22 >>
13 B or 1 22
23 2 27
W=LA+Do
W=12+2
W=14
SAY 14 ft
J.E. SCHRUM, E.I.
11/14/01